Answer with Step-by-step explanation:
We are given that A,B,C,D,E and F.
We have to find the number of different four -letter arrangements can be formed using given six letters a,if the first letter must be C and one of the other letters must be B and no letter can be used more than once in the arrangement.
Number of letters=6
We have to arrange four letter out of six
After fixing C and B then we choose only two letters out of remaining four letters and repetition is not allowed.
Permutation formula :
We have n=4 an r=2
Using this formula and substitute the values
Then, we get 

Hence, number of different four -letter arrangements can be formed using six letters when repetition is not allowed=12
Answer:
For the first question, the answer is 216 and the equation would become just 6^3
For the second, the answer is 9.
Step-by-step explanation:
When there is a negative exponent, that monomial is brought up to the top of the fraction, (the numerator) so 1/6^-3 becomes 1(6^3)/1, or simplified, just 6^3 since divided by one is the same number and times one is the same number. 6 x 6 x 6 is 216.
When there is a negative exponent outside the equation in a <u>fraction,</u> you need to take the reciprocal of the fraction. Since it's squared, it will always be positive, so we can ignore the negative sign. 3/1 (or just 3) to the power of 2 is 9. (3 x 3 is 9).
When explained throughly this might be found confusing, but it's a very easy concept to get after a while.
Answer:
It's 15
Step-by-step explanation:
17(1)=17
17-2=15