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3 years ago

Slope-intercept equation from graph (please help)

Mathematics

2 answers:

spayn [35]3 years ago

7 0

Answer: Y=4 x+-2

Step-by-step explanation:

Wewaii [24]3 years ago

6 0

9514 1404 393

Answer:

y = 2x +4

Step-by-step explanation:

The slope-intercept form of the equation of a line is ...

y = mx + b

where m represents the slope (rise/run), and b represents the y-intercept.

Here, the line increases by 2 units (rise=2) for each increase of 1 unit in the x-direction (run=1). Then the slope is ...

m = rise/run = 2/1 = 2

The graph crosses the y-axis at y=4, so the y-intercept value is ...

b = 4

Putting these values into the above slope-intercept form, we have ...

y = 2x + 4

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Location is known to affect the number, of a particular item, sold by HEB Pantry. Two different locations, A and B, are selected

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Answer:

d) [-16.03,-3.97]

$-16.03 \leq \mu_A -\mu_B \leq -3.97$ .

Step-by-step explanation:

Notation and previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$n_A=18$ represent the sample of A

$n_B =13$ represent the sample of B

$\bar x_A =39$ represent the mean sample for A

$\bar x_B =49$ represent the mean sample for B

$s_A =8$ represent the sample deviation for A

$s_B =4$ represent the sample deviation for B

$\alpha=0.01$ represent the significance level

Confidence =99% or 0.99

The confidence interval for the difference of means is given by the following formula:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2}\sqrt{(\frac{s^2_A}{n_A}+\frac{s^2_B}{n_B})}$ (1)

The point of estimate for $\mu_A -\mu_B$ is just given by:

$\bar X_A -\bar X_B =39-49=-10$

The appropiate degrees of freedom are $df=n_1+ n_2 -2=18+13-2=29$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,29)".And we see that $t_{\alpha/2}=2.756$