the answer is three look where it says 4-1 is 3
Answer:
A(2, -3) and B(3, -2), o(0, 0) Let C(x, y)
Here c divide AB line in the ratio of 1:2
From the line intersection law, we get x=(m1×x2+m2×x1)/(m1+m2)
and y=(m1×y2+m2×y1)/(m1+m2)
where m1=1, m2=2, x1=2, x2=3, y1=-3, y2=-2;
so x=(3+4)/3
or, x=7/3;
y=(-2-6)/3
or, y=-8/3;
so, oc=√((0-7/3)²+(0-(-8/3))²)
oc=3.54
Answer:
The domain and the range of the function are, respectively:
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
Step-by-step explanation:
Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.
Answer:
y = -(x + 5)² + 4
Step-by-step explanation:
The roots are -3 and -7, so:
y = a (x + 3) (x + 7)
Distribute and complete the square:
y = a (x² + 10x + 21)
y = a (x² + 10x + 25 − 4)
y = a (x² + 10x + 25) − 4a
y = a (x + 5)² − 4a
The vertex is (-5, 4), so a = -1.
y = -(x + 5)² + 4
