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lesantik [10]
3 years ago
9

Analyze the problem and complete the statements.

Mathematics
1 answer:
NARA [144]3 years ago
6 0

Answer:

I know this problem is an  

✔ equation

because it has an equals sign.

The t is the  

✔ variable

.

The negative sign is the  

✔ operation

.

The 7 and the 8 are both  

✔ constants

.

Step-by-step explanation: i took the test :( crying cuz im bouta fail

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Jen bought 5 equal-priced items. If the total tax for all the
8_murik_8 [283]
The answer should be D because everything else is true.
6 0
3 years ago
PLZ HELP ME ASAP!!!!!!!!
soldier1979 [14.2K]

THINK AND RELAX TAKE A DEEP BREATH

3 0
3 years ago
12'11"<br> + 11'3"<br> ‾‾‾‾‾‾
telo118 [61]

Answer:

24' 2 "

Step-by-step explanation:

12'11"

+ 11'3"

‾‾‾‾‾‾

23 '  14 "

But we know there are 12 inches in a foot so subtract 12 inches and add 1 ft

14-12 = 2"

23+1 = 24 ft

24' 2 "

7 0
4 years ago
6 Mateo and Katia each walked into a
inna [77]

Answer:

(amounts could be:)

Katia: $3.50

Mateo: $1.75

Step-by-step explanation:

<em>Remember that a quarter = $0.25, 4 quarters = $1.00</em>

<h3>We know that they both have 38 quarters ($9.50) </h3>

<em>after an hour of playing games in the arcade, Katia has $1.75 more than Mateo</em>

lets say that Katia has <em>(random amount)</em><em>$3.50(14 quarters) </em>and Mateo has $1.75 less than that.

$3.50 - $1.75 = $1.75

<h3>Katia has $3.50 and Mateo has $1.75.</h3>
7 0
2 years ago
HELP PLEASE
Arturiano [62]

The plane will end up flying 5.02°.

The plan's speed relative to the ground will be 645.91 km/hr.

Solution:

Use the cosine formula,

a^{2}=b^{2}+c^{2}-2 b c \cos A

Substitute the given values in the formula,

\mathrm{R}^{2}=700^{2}+80^{2}-(2 \times 700 \times 80 \times \cos 45^\circ)

\mathrm{R}^{2}=490000+6400-(112000 \times\frac{1}{\sqrt{2} } )

\mathrm{R}^{2}=496400-79195.95

\mathrm{R}^{2}=417204.049

Taking square root on both sides, we get

R = 645.91 km/hr

This is the grouped speed of the aircraft.

To find θ use sine rule.

$\frac{\sin C}{c}=\frac{\sin A}{a}

$\frac{\sin \theta}{80}=\frac{\sin 45}{645.91}

Do cross multiplication, we get

${\sin \theta}}=\frac{\sin 45}{645.91}\times 80

${\sin \theta}}=\frac{\frac{1}{\sqrt{2} } }{645.91}\times 80

sin θ = 0.0875

θ = 5.02°

This is known as the drift angle and is the correction the pilot should apply to remain on course.  

The heading is the direction the aircraft's nose is pointing which is

The track is the actual direction over the ground which is θ = 5.02°

An alternative method to this would be to separate each vector into vertical and horizontal components and add.

The resultant can be found using Pythagoras.

7 0
4 years ago
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