A triangle has two sides of length 12 and 6. What is the largest possible whole-number length
1 answer:
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Option C:
The perimeter of the rhombus is 100 inches.
Solution:
AC = 30 inches, BD = 40 inches
In rhombus, diagonals bisect each other at right angles.
AE = CE = 15 inches
BE = ED = 20 inches
In ΔAED, ∠E = 90°
Using Pythagorean theorem,
Taking square root on both sides, we get
AD = 25 inches
In rhombus, all sides are equal in length.
AD = DC = CB = BA = 25 inches.
Perimeter = AD + DC + CB + BA
= 25 + 25 + 25 + 25
= 100 inches
The perimeter of the rhombus is 100 inches.
Option C is the correct answer.