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3 years ago

I need help with this question can you help me?

Mathematics

1 answer:

ZanzabumX [31]3 years ago

5 0

Answer:

300, because yeah..........................

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Please help me, i have a test soon and i don’t understand this!

IrinaVladis [17]

Answer:

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Step-by-step explanation:

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2 years ago

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Find the slope of the line that passes through the points (-19, -4) and (13, -17).

Tasya [4]

Answer:

m = $\frac{-13}{32}$

Step-by-step explanation:

Two point slope formula = $\frac{y_{2} - y_{1} }{x_{2} - x_{1} }$

$\frac{-17 + 4}{13 + 19} = \frac{-13}{32}$

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3 years ago

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Zanzabum

14 x 10^3 = 14,000 (the elephants weight)

So the cat weighs 14 pounds

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4 years ago

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What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?

posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

$\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\$

$Since\ \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0$

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3 years ago

Pre Calculus Help! Will give Brainliest!

Sveta_85 [38]

It's a quotient identity

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3 years ago

I need help with this question can you help me?​

I need help with this question can you help me?