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3 years ago

15

(Will give brainiest to whoever answers correctly)PLEASE this is do tomorrow and I don't know how to do it, also explain step by

step how you got your answer

1 answer:

tia_tia [17]3 years ago

5 0

Answer:

64 guarts of ice-cream

8/5 quarts of ice-cream = 1/4 cake

x guarts of ice-cream = 10 cakes

cross multiply and find x you'd get 64

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The vertices of a trapezoid are located at (1, 2), (3, 1), (3, 5), (1, 4). The trapezoid is translated 4 units to the right. Wha

padilas [110]

Answer:

Suppose that we have a given point (x, y)

If we translate this point N units to the right, then the new coordinates of the point are:

(x + N, y)

Ok, now if we know that the vertices of the trapezoid are:

(1, 2), (3, 1), (3, 5), (1, 4)

And we move the whole figure 4 units to the right, then all the vertices are moved 4 units to the right.

Then the new vertices of the figure will be:

(1 + 4, 2) = (5, 2)

(3 + 4, 1) = (7, 1)

(3 + 4, 5) = (7, 5)

(1 + 4, 4) = (5, 4)

Then the coordinates of the image of the trapezoid (of the new vertices) are:

(5, 2), (7, 1), (7, 5), (5, 4)

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3 years ago

What number is 15% of 80?<br> use percent proportions

vova2212 [387]

!5% is equivalent to 15 parts over the whole 100 part. It is written in proportions as 15/100.

Similarly, you need to find how many parts in 80 are equivalent to 15%or 15/100. So, just equate both equation with x as an unknown.

x/80 = 15/100
x = (15/100)*80
x = 12

Thus, the 15% of 80 is 12.

8 0

3 years ago

Evaluate 20 + 6x when x = 0.

bulgar [2K]

Answer:

If x=0 then the answer is 20.

Step-by-step explanation:

7 0

2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

The derivative of (x^2 +1)(x^3+ 1) (by definition and basic rule)

dlinn [17]

Answer:

f'(x) = 5x^4 + 2x + 3x^2

Step-by-step explanation:

To find the derivative of this equation we can do two things.

One method is to use the product rule, which states that when f(x) consists of two functions multiplied to each other (meaning f(x) = g(x) * h(x)), the derivative is f'(x) = g'(x)*h(x) + g(x)*h'(x). In simple language, the derivative is found by finding the derivative of x² + 1 and multiplying it with the normal function of x³ + 1, after which you add the product of the nnormal function of x² + 1 and the derivative of x³ + 1.

it might be clearer when I show you:

$f(x) = (x^2 + 1)(x^3 + 1)\\f'(x) = (2x)(x^3 + 1) + (x^2 + 1)(3x^2)\\Simplify:\\f'(x) = 2x^4 + 2x + 3x^4 + 3x^2 = 5x^4 + 3x^2 + 2x\\$

If you are not familiar with this rule you can first write out the function and then use the basic rule:

$f(x) = (x^2 +1)(x^3+1) = x^5 + x^2 + x^3 + 1\\f'(x) = 5x^4 + 2x + 3x^2$

If you need any further help please say so in the comments! I hope this helps! If the steps seem complicated, I suggest you could revise expanding brackets (the first step of the second method) and the basic rules of deriving, but feel free to reach out if you struggle afterwards still

8 0

3 years ago