It's 72
the measure of exterior angle of any regular polygon = 360/number of sides = 360/5 = 72°
3√27/1000
=3/10 is your final answer. Hope it help!
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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Now let's examine the statements:
A)The functions have the same range:FALSE the range changed from y ≥ 0 to y ≤ 0
B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0
C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.
D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.
E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.
F)The range of g(x) is all values less than or equal to 0. TRUE: it was proved above.