All categories

2 years ago

Enrique has to pay 80% of a $200 phone bill. Explain how to use equivalent ratios to find 80% of $200.

Mathematics

2 answers:

Tanzania [10]2 years ago

7 0

<u>Answer:</u>

First, write 80% as 80/100. Then write an equivalent ratio that has the answer in the numerator and 200 in the denominator. 100 x 2 is 200, so 80 x 2 will be the answer. 80 x 2 = 160. The answer is $160.

<u>Step-by-step explanation:</u>

It was the sample response, hope this helps. :-)

Virty [35]2 years ago

5 0

Answer:

multiply 200 by .8

its 160

Step-by-step explanation:

You might be interested in

Jodi poured herself a cold soda that had an initial temperature 36 degrees F and immediately went outside to sunbathe where the

mr Goodwill [35]

this can be solve using newtons heating of cooling

(Ts – T) =(Ts – To)*e^(-kt)

Where Ts is the ambient temperature

To is initial temperature

T is the temperature at time t

t is the time

k is constant

fisrt solve the constant k for the given first scenario

(99 – 36) = (99 – 46)*e(-5k)

K = -0.0346

Using k, solve T at t = 13 min

(99 – 46) = (99 – T)*e(-13*(-0.0346)

T = 58.82 degree F

4 0

3 years ago

2) The sum of 5x and 2x is at least 14

Semmy [17]

Answer:

Step-by-step explanation:

if it is less than 14 then the big side of the arrow would be facing the 14

6 0

3 years ago

Read 2 more answers

A selective college would like to have an entering class of 950 students. Because not all students who are offered admission acc

pogonyaev

Answer:

a) The mean is 900 and the standard deviation is 15.

b) 100% probability that at least 800 students accept.

c) 0.05% probability that more than 950 will accept.

d) 94.84% probability that more than 950 will accept

Step-by-step explanation:

We use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .