OMGG SIS I HAVE I READY TO ILL HELP YOU :DDD
Answer:
Step-by-step explanation:
S=student cost; T=teacher cost
.
32S+3T=$127 . Multiply this by 2.
64S+6T=$254 Subtract this below
.
25S+2T=$97.50 . Multiply this by 3.
75S+6T=$292.50
64S+6T=$254 . Subtract this (from above.)
.
11S=$38.50
S=$3.50
ANSWER 1: Student tickets cost $3.50.
.
32S+3T=$127
32($3.50)+3T=$127
$112+3T=$127
3T=$15
T=$5.00
ANSWER 2: Teacher tickets cost $5.00.
.
CHECK:
25S+2T=$97.50
25($3.50)+2($5.00)=$97.50
$87.50+$10.00=$97.50
$97.50=$97.50
Answer:
322.28
A
Step-by-step explanation:
Area of the rectangle
L = 30
W = 21
Area = 30 * 21
Area = 630
Area of the circles
Radius = 7 m
Area = pi r^2
Area = 3.14 * 7^2
Area = 153.86 m^2
Area of both circles = 307.72
Area of the Shaded Region
Area of shaded region = area of the rectangle - area of 2 circles.
Area of Shaded Region = 630 - 307.72
Area of Shaded Region = 322.28
Answer:
(72-40) = 8 x (9-5)
Step-by-step explanation:
GCF = 8
(72-40) = 8 x (9-5)
Answer & Step-by-step explanation:
Using the information given in the question we can form the following 3 equations (in the order of the first 3 sentences)
w = 2h (twice the price)
t = h - 4 ($4 less)
3w + 2h + 5t = 136 (total purchasing and cost)
We can solve all 3 equations for h first, by substituting the first two equations, into the third equations w and t
3(2h) + 2h + 5(h-4) = 136
Simplify
6h + 2h + 5h - 20 = 136
13h = 136 + 20
13h = 156
h = 156/13
h = $12
Using this information, we can solve for w and t
w = 2h
w = 2(12)
w = $24
And finally
t = h - 4
t = 12 - 4
t = $8
