Answer:
24.6 < μ < 27.2
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.9 - 1.3 = 24.6 pounds.
The upper end of the interval is the sample mean added to M. So it is 25.9 + 1.3 = 27.2 pounds.
So the correct answer is:
24.6 < μ < 27.2
Answer:
(-3y5)3
-9y15
Step-by-step explanation:
prove me wrong
Answer:
C. the initial number of club members, in hundreds
Step-by-step explanation:
The general form of such an expression is ...
(initial value)×(growth factor per period)^(number of periods)
The use of 12 in the exponent suggests that the growth factor of 1.02 is an annual factor. If that is the case, for t months, the membership should be modeled as ...
1.8(1.02^(t/12))
_____
As written, the expression is not an exponential expression. With appropriate parentheses, it might be a good model if t is the number of <em>years</em> (not <em>months</em>), and if the expected growth rate is 2% per month.
1.8(1.02^(12t))
Let x = amount of sales (in dollars)
The salary is $400 and there's an additional 0.06x dollars added on to get to the goal of 790. The equation is therefore
<span>400+0.06x = 790
</span>
Let's solve for x
400+0.06x = 790
<span>400+0.06x-400 = 790-400
</span>0.06x = 390
0.06x/0.06 = 390/0.06
x = 6500
The final answer is 6500
This means he must have $6,500 in sales.
