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anzhelika [568]
3 years ago
5

Is 1563/25 a rational number

Mathematics
2 answers:
kupik [55]3 years ago
6 0

Answer:

Yes, it's a rational number

Step-by-step explanation:

can be written as fraction and integers

Allushta [10]3 years ago
5 0
Yes it is bc i know:)))
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Pls, help due in 30 mins!! it is math.
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2. scale factor 2 | x = 4.5

3. scale factor 1.5 | x = 12

Step-by-step explanation:

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Find the missing number.<br><br> n − 9.01 = 3.86<br><br> n = ?
aleksandr82 [10.1K]
I think the missing number should be
12.87
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marysya [2.9K]

Answer:

10 miles is the correct answer

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2 years ago
Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that
Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is \\ P(x>76) = 0.99865.

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> \\ \mu and the <em>population standard deviation</em> \\ \sigma.

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are \\ \mu = 0 and \\ \sigma = 1. However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

\\ \mu = 85

\\ \sigma = 3

\\ x = 76

From equation [1], we have:

\\ z = \frac{76 - 85}{3}

Then

\\ z = \frac{-9}{3}

\\ z = -3

Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of \\ z = -3, we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

\\ P(z>-3) = 1 - P(z>3) = P(z

Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

\\ P(z

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, \\ \mu = 85 and \\ \sigma = 3) is \\ P(x>76) = P(z>-3) = P(z.

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

\\ P(z3)

\\ P(z3)

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

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3 years ago
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ELEN [110]

<u>Answer</u>:

13. 6x^7 y^7   ||     14. \frac{25x^4}{y^6}

<u>explanation</u>:

13.

\frac{12x^9 y^5}{2x^2 y^-2}

6x^{9-2} y^{5--2}

6x^7 y^7

14.

(\frac{5y^{-3} }{x^{-2} } )^{2}

(\frac{5y^{-3} }{x^{-2} } )(\frac{5y^{-3} }{x^{-2} } )

\frac{\frac{25}{y^6}}{\left(x^{-2}\right)^2}

\frac{\frac{25}{y^{-6} }}{\left(x^{-4}\right)}

\frac{25x^4}{y^6}

4 0
2 years ago
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