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MA_775_DIABLO [31]
3 years ago
9

If I make $2000 a month, how much will I make per week?

Mathematics
2 answers:
anzhelika [568]3 years ago
5 0
500 is the answer

Explaination



Because it’s right
Arisa [49]3 years ago
4 0

Answer:

You would make about $500 per week

Step-by-step explanation:

There are about 4 weeks per month

2,000 ÷ 4 = 500

So ~ 500 per week

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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Help asap!!!!!!!!!!!
kenny6666 [7]

Answer:

hi there I am Madhumita a good time to explore new ways of learning and smart ways of learning and smart ways of earning a living the good work he is there a way to get lost in the given equation of state for the diagram

6 0
3 years ago
Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot
Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

\frac{dm}{dt} = -\frac{t}{\tau}

Where:

m - Current mass of the isotope, measured in kilograms.

t - Time, measured in days.

\tau - Time constant, measured in days.

The solution of the differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

The half-life of a isotope (t_{1/2}) as a function of time constant is:

t_{1/2} = \tau \cdot \ln2

t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2

The half-life difference between isotope B and isotope A is:

\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|

If \frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9, t_{A} = 33\,days and t_{B} = 43\,days, the difference in the half-lives of the isotopes is:

\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|

\Delta t_{1/2} \approx 65.788\,days

The approximate difference in the half-lives of the isotopes is 66 days.

4 0
3 years ago
Read 2 more answers
Factor f(x)=x2−8x+16<br><br> (A) (x−4)2<br> (B) (x+8)2<br> (C) (x−8)2<br> (D) (x+4)2
Fynjy0 [20]

Answer:

A

Step-by-step explanation:

(x-4)^2 = x^2 -4x -4x + (-4)*(-4)

= x^2-8x+16 as required

3 0
3 years ago
Question 3 (Essay Worth 10 points)
Vika [28.1K]

Answer:

a) A= Lenght *Width

And replacing we got:

A= (3x+10) (4x+5)

And simplifying we got:

A = 12x^2 +15x +40x +50 = 12x^2 +55x +50

b) For this case since the coeficient for the higher degree is 2 then the polynomial is of second degree.

c) We need to remember that the closed property for polynomials tell to us that if we apply any operation between two polynomials we need to obtain and other polynomial. For this special case the property is the sum and after multiply we have another polynomial with a higher degree and then the closed property is satisfied.

Step-by-step explanation:

We know a  rectangle has sides measuring (4x + 5) units and (3x + 10) units

Part a

For this case we can find the area like this:

A= Lenght *Width

And replacing we got:

A= (3x+10) (4x+5)

And simplifying we got:

A = 12x^2 +15x +40x +50 = 12x^2 +55x +50

Part b

For this case since the coeficient for the higher degree is 2 then the polynomial is of second degree.

Part c

We need to remember that the closed property for polynomials tell to us that if we apply any operation between two polynomials we need to obtain and other polynomial. For this special case the property is the sum and after multiply we have another polynomial with a higher degree and then the closed property is satisfied.

5 0
3 years ago
Which term of the AP:3,15,27, 39,.....will be 132 more than its 54th term​
horsena [70]

Answer:

n=65th term

Step-by-step explanation:

AP:3,15,27,39......

From the AP

a=3

a+d=15

a+2d=27

3+d=15 (1)

3+2d=27 (2)

Subtract (1) from (2)

We have,

2d-d=27-15

d=12

54th term=a+(n-1)d

=3+(54-1)12

=3+(53)12

=3+636

=639

The term is 132 more than the 54th term

132+54th term

=132+639

=771

Find the term

771=a+(n-1)d

771=3+(n-1)12

771-3=12n-12

768=12n-12

768+12=12n

780=12n

n=780/12

=65

n=12

The term which is 132 more than the 54th term is the 65th term

4 0
3 years ago
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