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Andrews [41]
3 years ago
13

Using sets what is the intersection of a=(-2-1,0,1,7) I=(-2,-1,1,2,8)​

Mathematics
1 answer:
polet [3.4K]3 years ago
4 0
The answer is (-2,-1,1)
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What is 750x+150<1000
liberstina [14]

Answer:

x

Step-by-step explanation:

We begin with the inequality: 750x+150

We need to solve for x. This means that we need to subtract 150 from each side and then divide each side by 750. Then we need to simplify.

750x+150

7 0
4 years ago
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Incomes in a certain town are strongly right-skewed with mean $36,000 and standard deviation $7000. a random sample of 75 househ
Svet_ta [14]
Since the sample is greater than 10, we can approximate this binomial problem with a normal distribution.

First, calculate the z-score:

z = (x - μ) / σ = (37000 - 36000) / 7000 = 0.143

The probability P(x > 37000$) = 1 - P(<span>x < 37000$), 
therefore we need to look up at a normal distribution table in order to find 
P(z < 0.143) = 0.55567 
And 
</span>P(x > 37000$) = 1 - <span>0.55567 = 0.44433

Hence, there is a 44.4% probability that </span><span>the sample mean is greater than $37,000.</span>

4 0
4 years ago
John's gross monthly salary is $2,000 starting next month, John receives a 15% raise power month. also starting next month, 30%
timama [110]

John's gross monthly salary is $2000.

John receives a 15% raise in his salary.

So first we have to find 15% of $2000.

15% of 2000 = (2000)(\frac{15}{100})

= \frac{(2000)(15)}{100}

= \frac{30000}{100}

= 300

John's salary including the raise = $(2000+300) = $2300.

Now 30% of his monthly paycheck withheld for taxes.

30% of 2300 = (2300)(\frac{30}{100})

= \frac{(2300)(30)}{100}

= \frac{69000}{100}

= 690

So the amount of tax deducted = $690.

John's net monthly income = $ (2300-690) = $1610.

So we have got the required answer.

5 0
3 years ago
Solve the problem. For a standard normal distribution, find the percentage of data that are between 3 standard deviations below
solong [7]

Answer:

83.85%

Step-by-step explanation:

We will use the empirical rule. For a standard normal distribution the mean is equal to 0 and the standard deviation is equal to 1. Then, between 3 standard deviations below the mean, we have 2.35% + 13.5% + 34% = 49.85% of data, and 1 standard deviation above the mean we have 34% of data. Therefore, the percentage of data that are between 3 standard deviations below the mean and 1 standard deviation above the mean is 49.85%+34% = 83.85%.

7 0
4 years ago
PLEASE HURRY ASAP!!!!!!!! ( select all that apply)
Neporo4naja [7]
The first one is true, so is the fourth one. The second one is not true and I'm not sure about the 3rd one, you would have to write them all out in numerical order and find the one in the middle
7 0
3 years ago
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