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Lubov Fominskaja [6]
3 years ago
13

Solve the system of equations given below. y - 15 = 3 -2.1 + 5y = -3

Mathematics
1 answer:
EastWind [94]3 years ago
3 0

Answer:

1) y=18

2)y=-0.18

Step-by-step explanation:

1) y-15=3. Add 15 on both sides.

y=18

2)-2.1+5y=-3. Add 2.1 on both sides

5y=-0.9. Divide 5 on both sides

y=-0.18

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Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answ
tekilochka [14]

Answer:

a

  df =  24.32

b

 df = 30.10

c

 df = 30.7

d

df = 25.5

Step-by-step explanation:

Generally degree of freedom is mathematically represented as

          df =  \frac{ [\frac{ s^2_i }{m} + \frac{ s^2_j }{n} ]^2 }{ \frac{ [ \frac{s^2_i}{m} ]^2 }{m-1 }  +\frac{ [ \frac{s^2_j}{n} ]^2 }{n-1 }  }

Considering a

         a) m = 12, n = 15, s1 = 4.0, s2 = 6.0

           df =  \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{15} ]^2 }{ \frac{ [ \frac{4^2}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{15} ]^2 }{15-1 }  }

         df =  24.32

Considering b

       (b) m = 12, n = 21, s1 = 4.0, s2 = 6.0

          df =  \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{4^4}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 }  }

        df = 30.10

Considering c

      (c) m = 12, n = 21, s1 = 3.0, s2 = 6.0

           df =  \frac{ [\frac{ 3^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{3^4}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 }  }

           df = 30.7

Considering c

        (d) m = 10, n = 24, s1 = 4.0, s2 = 6.0

                df =  \frac{ [\frac{ 4^2 }{10} + \frac{ 6^2 }{24} ]^2 }{ \frac{ [ \frac{4^2}{10} ]^2 }{10-1 }  +\frac{ [ \frac{6^2}{24} ]^2 }{24-1 }  }

               df = 25.5

   

3 0
3 years ago
Find the 10th term of the following geometric sequence.<br> 2, 10, 50, 250, ...
defon

Answer:

3906250

Step-by-step explanation:

We can notice that the ratio is 5. 10/2 = 5

Each term gets multiplied by 5 to get the next term.

250 × 5 = 1250 (5th term)

1250 × 5 = 6250 (6th term)

6250 × 5 = 31250 (7th term)

31250 × 5 = 156250 (8th term)

156250 × 5 = 781250 (9th term)

781250 × 5 = 3906250 (10th term)

The 10th term of the geometric sequence is 3906250.

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4 years ago
4.23 rounded to the nearest tenth
mestny [16]
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5 0
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slava [35]

Answer:

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Step-by-step explanation:

To solve this, lets take the first equation and find the x value.

Because it is ordered in standard form, we need to convert to slope-intercept form, and isolate the y.

5x+4y=16

-5x       -5x

4y=-5x+16

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y=\frac{-5}{4}+4

or

y=-1\frac{1}{4}+4

or

y= 5\frac{1}{4}

Now that we have the y value, we can use this to find the x value by inserting it into either equation, since they both have y values in them. Going with the first one again, lets try it:

5x+4(\frac{-5}{4}+4)=16

5x-5+16=16

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