Question

Write the standard form equation of the line through the given points. through (0.-4) and (-3,-2)

Answer 1

Answer:

The standard form of equation of the line through the given points. through (0.-4) and (-3,-2) is $\frac{2}{3}x+y=-4$

Step-by-step explanation:

The standard form of equation is $Ax+By=C$

Finding slope

Using the given points (0,-4) and (-3,-2) we can find slope using formula:$Slope=\frac{y_2-y_1}{x_2-x_1}$

$Slope=\frac{-2-(-4)}{-3-(0)}\\Slope=\frac{-2+4}{-3} \\Slope=-\frac{2}{3}$

Finding y-intercept

Using point (0,4) and Slope=-2/3 we can find y-intercept

$y=mx+b\\-4=-\frac{2}{3}(0)+b\\-4=0+b\\b=-4$

The slope intercept form of the line through the given points. through (0.-4) and (-3,-2) having slope =-2/3 and b=-4 will be:

$y=mx+b\\y=-\frac{2}{3}x-4$

Now, standard form of equation will be: $\frac{2}{3}x+y=-4$

So, The standard form of equation of the line through the given points. through (0.-4) and (-3,-2) is $\frac{2}{3}x+y=-4$