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3 years ago

The trajectory of a golf ball hit from a tee on the ground at an angle of 40 degrees with an initial

Mathematics

1 answer:

Finger [1]3 years ago

8 0

Answer:

53.45 m
254.55 m

Step-by-step explanation:

Given function:

f(x) = 0.84x - 0.0033x²

Rewrite in the standard form:

f(x) = - 0.0033x² + 0.84x

The maximum height is the vertex with x- coordinate -b/2a, which is:

x = -0.84/2(-0.0033) ≈ 127.27

The highest point is:

f(127.27) = -0.0033(127.27)² + 0.84(127.27) ≈ 53.45 m

The horizontal distance the golf ball travels before hitting the ground:

f(x) = 0
- 0.0033x² + 0.84x = 0
33x² - 8400x = 0
x(33x - 8400) = 0
x = 0- initial point
33x = 8400 ⇒ x = 8400/33 ≈ 254.55 m

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What is the equation of the line that passes through the point (-1, 4) and has a slope of -5?

AfilCa [17]

Answer:

Step-by-step explanation:

y - 4 = -5(x + 1)

y - 4 = -5x - 5

y = -5x - 1

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3 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

WORTH 49 POINTS! How far away is -5 to |-5|?

diamong [38]

|-5| is equivalent to 5, since that is how far -5 is from 0.

So, the question is simplified to: How far away is -5 from 5?

We get 5-(-5)=10.

Remember, absolute value is always positive (expect for 0) and the distance between two numbers is always positive (expect for 0).

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3 years ago

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What is the common difference in this sequence: 4, 13, 22, 31, 40?

IgorC [24]

Answer:

Step-by-step explanation:

To find the common difference, take the second term and subtract the first term

13-4 =9

Lets check:

Take the third term and subtract the second term

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The common difference is 9

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If a rope is 36 feet long and cut into 8 sections what is the length in feet of each section

tigry1 [53]

Answer:

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Step-by-step explanation:

In order to get the answer, you will divided 36 by 8. When you divide, you then get 4 4/8 which is then reduced to 4 1/2. Hope this helps! :)

<h2>CloutAnswers</h2>

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3 years ago

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