Question

The trajectory of a golf ball hit from a tee on the ground at an angle of 40 degrees with an initial

Answer 1

Answer:

• 53.45 m
• 254.55 m

Step-by-step explanation:

Given function:

• f(x) = 0.84x - 0.0033x²

Rewrite in the standard form:

• f(x) = - 0.0033x² + 0.84x

The maximum height is the vertex with x- coordinate -b/2a, which is:

• x = -0.84/2(-0.0033) ≈ 127.27

The highest point is:

• f(127.27) = -0.0033(127.27)² + 0.84(127.27) ≈ 53.45 m

The horizontal distance the golf ball travels before hitting the ground:

• f(x) = 0
• - 0.0033x² + 0.84x = 0
• 33x² - 8400x = 0
• x(33x - 8400) = 0
• x = 0- initial point
• 33x = 8400 ⇒ x = 8400/33 ≈ 254.55 m