You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
30 x 30 = 900
This is the surface area of one side
900 x 6
Multiply by 6 to get the surface area of all 6 sides of the cube
900 x 6 = 5400
Answer:
x / 3 = -8
Step-by-step explanation:
Answer:
26.4ft²
Step-by-step explanation:
I first converted the centimeter values to feet
140Cm x 30.48 = 4.59
70cm x 30.48 = 2.3
the paper required is approximately equal to the area of the pyramid.
area of pyramid is equal to area of triangle + base²
Are of triangle = 1/2 x b xh
= 4 x 1/2 x4.59x2.3 + (2.3)²
= 2 x 4.59 x 2.3 + 5.29
= 26.4 feet²
therefore it will take 26.4 feet² paper to make each tree, including the bottom.