Answer:
usual number of yellow eggs = 12
Usual maximum = 21
Usual minimum = 3
Step-by-step explanation:
To solve this, we will use the expected value of a binomial probability.
The formula is;
E(X) = np
Where;
n is sample size
p is probability of success.
We are given;
n = 58
p = 21%
Thus;
usual number of yellow eggs in samples = np = 58 × 21% = 12.18 ≈ 12
From USL(Upper specification limit) and LSL(Lower specification limit) formula, we can find the maximum usual number and minimum usual number of eggs respectively.
Thus;
USL = n(p + 3√(p(1 - p)/n)
USL = 58(0.21 + 3√(0.21(1 - 0.21)/58)
USL = 21.48 ≈ 21
LSL = n(p - 3√(p(1 - p)/n)
LSL = 58(0.21 - 3√(0.21(1 - 0.21)/58)
LSL = 2.87 ≈ 3
Answer:
x=8
NR=5 units
BI=10 units
Step-by-step explanation:
In a rectangle BRIA
AN=5 units
NR=x-3
We have to solve for x , NR and BI.
We know that
Diagonals of rectangle bisect to each other.
BI and AR are the diagonals of rectangle BRIA and intersect at point N.
AN=NR
Substitute the value of x
NR=8-3=5
By property of rectangle
BI=AR=AN+NR=5+5=10 unit
BI=10 units
He can buy 6 water bottles that are $3 a piece.
