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Reil [10]
2 years ago
11

Ms. Farmer has 33 students in her class. This is 11 more

Mathematics
1 answer:
EleoNora [17]2 years ago
7 0

Answer: C

Step by step explanation :

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Chloe has a bird feeder in her yard. When it is full of bird seed, it weighs 12 3/4 pounds. The birds eat 1 1/2 pounds of bird s
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B

Step-by-step explanation

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What is the equation of the line containing the points (5,2),(10,4)and (15,6)
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The y/x values all have the same ratio, 2/5. The line is

y = (2/5)x
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What way of warming up is preferred before exercise? *
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Answer:   B!

Step-by-step explanation:  The best way to warm up before taking part in physical activity is to perform low-intensity, dynamic movements that are similar to the main type of activity that you will perform.

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2 years ago
Read 2 more answers
A newspaper poll asked respondents if they trusted "eco friendly" labels on cleaning products. Out of 1000 adults surveyed, 498
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Answer:

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.  

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=498 represent the adults that trust these labels

\hat p=\frac{498}{1000}=0.498 estimated proportion of respondents that trust these labels

p_o=0.5 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of respondents that trust these labels is at least 50%:  

Null hypothesis:p\geq 0.5  

Alternative hypothesis:p < 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.498 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=-0.126  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided but we can assume it as \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.  

7 0
3 years ago
The parents of a hospitalized 3-month-old have to leave the infant while they work. One parent fears that the baby will cry as s
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1. “ at this age , my baby will not cry because we are leaving.”
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