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2 years ago

6

Given cos(O)=3/5 and tan(O)

1 answer:

Valentin [98]2 years ago

3 0

Answer:

Tan(O) = 4/3

Step-by-step explanation:

According to SOH CAH TOA

cos theta = adj/hyp

cosO = 3/4

adj = 3

hyp = 5

Get the opposite

Using pythagoras theorem

opp^2 = hyp^2-adj^2

opp^2 = 5^2 - 3^2

opp^2 = 25-9

opp^2 = 16

opp = 4

Tan (O) = opp/adj

Tan(O) = 4/3

Hence Tan(O) = 4/3

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Answer:

See Below

Step-by-step explanation:

We are given 3 equations.

3x + 8

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and

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3x + 8 = 5x -20

Move the variables to one side

3x + 8 = 5x -20

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8 = 2x -20

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28 =2x

28/2 =2x /2

14 = x

Now we have x = 14

Lets plug this into the second equation to solve for the angle

3(14) + 8

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70 - 20 =50

Now, lets plug the x and the angle into the third equation to find y

5 (14) +4y = 50

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-70 -70

4y = -20

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y = -5

So now we have:

x = 14

y = -5

and the angle = 50

Hope this helps!

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Step-by-step explanation:

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