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11Alexandr11 [23.1K]
3 years ago
11

9 cans of paint are needed to

Mathematics
1 answer:
marusya05 [52]3 years ago
8 0
22.5 cans exactly should be used. So, if you round, 23 need to be bought because I am sure you can’t buy 22.5 cans.
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Find K if 4 x square - 2 X square + kx + 5 leaves a remainder -10 when divided by 2x+1​
ella [17]

Answer:

k = 31

Step-by-step explanation:

Given

f(x) = 4x^2 - 2x^2 + kx + 5

r = -10 --- remainder

d = 2x + 1 --- divisor

Required

Find k

We have:

d = 2x + 1 --- divisor

Equate to 0

2x + 1 = 0

Solve for x

2x = -1

x  =-0.5

This means that:

f(-0.5)=-10

So, we have:

4*(-0.5)^2 - 2*(-0.5)^2 + k*-0.5 + 5 =-10

0.5 -0.5k + 5 =-10

Collect like terms

-0.5k=-10-5-0.5

-0.5k=-15.5

Solve for k

k = -15.5/-0.5

k = 31

8 0
3 years ago
WILL GIVE PONITS
sergey [27]

Answer:

Jisjsjjsjejeneneinnjojoejejjekekkejeejjejejenjejekkjjrjejejebebhehejehhghxhxhjsjsbhdiejehbe

Hirap math nanaman

5 0
3 years ago
Will give brainilest if correct Element X decays radioactively with a half life of 15 minutes. If there are 770 grams of Element
Archy [21]

Answer:

The time it'd take for the element to have 15 g of mass is approximately 68 min.

Step-by-step explanation:

The radioactive decay of a substance is given by the following formula:

Since the element has a half life of 12 minutes, this means that after this time the mass of the element will be half of it was originally, therefore:

Therefore the mass of the element is given by:

If the initial mass is 760 g and the final mass is 15 g, we have:

The time it'd take for the element to have 15 g of mass is approximately 68 min.Step-by-step explanation:

5 0
3 years ago
Need help with the question in the attachment!
IceJOKER [234]

Answer:

The answer is 8.

Step-by-step explanation:

I used the calculator...

I just typed these equations on the calculator because its hard to do it in your head.

log 5root5 125 = 2 x=2

log 2root2 64 = 4 y= 4

The question wants the product of x and y which translates to x times y. x*y

SO.... 2*4 = 8

4 0
3 years ago
Can someone reply with how this works
soldier1979 [14.2K]
Uhm I think you forgot something
7 0
3 years ago
Read 2 more answers
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