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3 years ago

The missing angle of (3x-5)

Mathematics

2 answers:

iris [78.8K]3 years ago

5 0

Answer: 22

Step-by-step explanation:

(7x+5) + (3x-5) + 90 = 180

10x + 90 =180

-90 -90

10x =90

_ _

10 10

x = 9

3(9)-5

27-5

Andreyy893 years ago

4 0

Answer:

To find the missing angles of the triangle we must first make an equation using what we know. A triangles sum is equal to 180 degrees, and a box indicator represents a 90 degree angle. With that we do this,

(7x+5)+(3x-5)+90=180
7x+5+3x-5+90=180
7x+3x+90=180
10x+90=180
10x=180-90
10x=90
10x/10=90/10
x=9

Now we find each individual missing angle,

(3x-5)
3(9)-5
27-5
22 degrees

(7x+5)
7(9)+5
63+5
68 degrees

Check to make sure it equals 180 degrees

22+68+90=180

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∆ABC ~ ∆DEF. If ∠A=35° and ∠E=55°, what is the measure of ∠C?

madam [21]

Answer:

90°

Step-by-step explanation:

ABC ~ DEF so that means E = B. A triangle has to add up to 180° so that means 180-35-55=90

7 0

3 years ago

HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

3 years ago

G 3.6 Dice rolls. If you roll a pair of fair dice, what is the probability of (a) getting a sum of 1

Paladinen [302]

Answer:

Step-by-step explanation:

In the roll of a pair of fair dice, The sample space is as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

If x,y represent the possible outcome of rolling the two die

Then the total number of possibilities for the sample space = (x,y)

= (6 × 6) = 36

Now, the probability of getting a sum of 1 does not exist in the roll of a pair of fair dice.

Therefore, Probability(1) = 0

8 0

3 years ago

Need help with question 2

yuradex [85]

1,5,8 would be the correct answer

8 0

3 years ago

Read 2 more answers

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Yanka [14]

I'm not sure if I did this right.

Answer:

Step-by-step explanation:

$1^2+x^2=\sqrt{5}^2$

$x^2+1=5$

$x=\frac{+}{-} \sqrt{4}$

2 or -2

8 0

3 years ago