Answer:
2.82843
Step-by-step explanation:
it was what i got
Answer:
For the values: 44, 30, 21
<span>The </span>LCM<span> is: </span><span>4620</span>
Answer:
The probability that Karen has bought at least one dented can is 82.5%
Step-by-step explanation:
To know the probability of Karen buying at least one dented can, it's easier to calculate the probability of her not buying any dented can, and we know that:
The probability of a can not being dented is (in the same principle as above, 100%(all cans)-7%(dented cans)=93%(non-dented cans) 0.93.
As the probability of a can being dented or not is independent from each other, we multiply the probabilities:
Now, we calculate the probability of at least one dented can, expressed as a percentage:
Answer:
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Solving
2X + 3Y = 5.5
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Simplifying
2X + 3Y = 5.5
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<u>Solving for variable 'X'.
</u>
<u>
Move all terms containing X to the left, all other terms to the right.</u>
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Add -3y to each side of the equation.
2x + 3y + -3y = 5.5 + -3y
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Combine terms: 3y + -3y = 0.
2x + 0 = 5.5 + -3y
2x = 5.5 + -3y
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Divide each side by 2.
x = 2.75 + -1.5y
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Simplifying.
x = 2.75 + -1.5y
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Case 1: You have an Ace and a seven.
There are 4 ways to pick 1 Ace out of 4. There are 4 ways to pick 1 seven out of 4. -----> 4*4 = 16
There are 16 ways to be dealt an Ace and a seven.
Case 2: You have a two and a six.
In the same way there are 4*4=16 ways to be dealt a two and a six.
Case 3: You have a three and a five.
In the same way there are 4*4=16 ways to be dealt a three and a five.
Case 4: You have 2 fours.
There are 6 ways to get 2 fours out of 4. (4 choose 2)
Total number of outcomes = 16+16+16+6 = 54
