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mamaluj [8]
3 years ago
13

Solve the simultaneous equations by substitution 8x – 3y = 5 3y = 2x + 1

Mathematics
2 answers:
tatuchka [14]3 years ago
8 0

Answer:

x = 1

y = 1

Step-by-step explanation:

this should be your answer

satela [25.4K]3 years ago
8 0

Answer:

(1, 1 )

Step-by-step explanation:

Given the 2 equations

8x - 3y = 5 → (1)

3y = 2x + 1 → (2)

Substitute y = 2x + 1 into (1)

8x - (2x + 1) = 5

8x - 2x - 1 = 5

6x - 1 = 5 ( add 1 to both sides )

6x = 6 ( divide both sides by 6 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for y

Substituting into (2)

3y = 2(1) + 1 = 2 + 1 = 3 ( divide both sides by 3 )

y = 1

solution is (1, 1 )

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4 years ago
FACTOR EACH EXPRESSION, IF IT CANT BE FACTORED WRITE CANNOT BE FACTORED. 1. 4x+12
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The greatest common factor is 4. Put this outside of the parentheses.             (You would multiply the 2*2)
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4x+12

2.) 2(4r+7)
Find the GCF of 8r and 14
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The greatest common factor is 2.                                                                 (There is only 1 two, so you would not multiply them.)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
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To check, distribute to see if it works.

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-15: -1*5*3

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6.)  8(4x+3)
7.) 3(2x-3)
8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)



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