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2 years ago

I got an answer but im really not sure if its right so please help

Mathematics

2 answers:

Vladimir79 [104]2 years ago

5 0

Answer:

60 degrees.

Step-by-step explanation:

Since you know that y = 74 because they are vertical angles, and 46 = the angle across from it (there is a theorem for it). Since one line is 180 degrees, and you already know the two sides next to x, which is 74 and 46, you can do 180 - 74 - 46. Your final answer should be 60 degrees.

igor_vitrenko [27]2 years ago

3 0

Answer:

60°

Step-by-step explanation:

so we need to find x

we are given 2 angles 46° and 74° which is in the middle of those numbers.

add 46° + 74° = 120°

since a straight line is 180° subtract 180° by 120° to get 60° = x.

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The area of a rectangular invitation card is 3/10 square foot. given that the length of the card is 4/5 foot, find its perimeter.

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2 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

1 year ago

1+1-1......................help plz due in 20 secs

kap26 [50]

1 is ur answer Step-by-step explanation:

4 0

2 years ago

3x + 5 = x - 3

dusya [7]

Answer:

x = -4

Step-by-step explanation:

3x + 5 = x - 3

Subtract x from each side

3x+5-x = x-3-x

2x+5 = -3

Subtract 5 from each side

2x+5-5 = -3-5

2x = -8

Divide each side by 2

2x/2 = -8/2

x = -4

7 0

2 years ago

Read 2 more answers

During a period of 30 working days, Deborah was late 80% of the time. How many days was she late?

erik [133]

Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.

Num days late = 0.8 * 30=24

So Deborah was late 24 out of 30 working days. Would appreciate a brainliest

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2 years ago