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Trava [24]
3 years ago
10

an oil company uses cylindrical storage tanks. each tank has a radius of 14ft and is 27ft fall. what is the volume of the tank?

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

378

Step-by-step explanation:

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Answer:

x = 25

Step-by-step explanation:

Here's my work. Basically, I knew that the x in angle A is alternate interior to angle C, so they would both be x. the 50 degrees is one a 180 degree line, so the inside of the triangle DCB is 130. X must equal x, so they would both be 25 degrees.

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G the population of a town today is 48000 people. if the population decreases with a constant rate of change and the decrease is
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The population in ten years will be 208,000
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Can someone help me i will give brainliest to whom ever right 28=x+13
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The answer is that x equals 15
6 0
2 years ago
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On a coordinate plane, an absolute value graph starts at (0, 0) and goes up and to the left through (negative 4, 2). The functio
natka813 [3]

Answer:

The function f(x)= –StartRoot negative x EndRoot is shown on the graph.

On a coordinate plane, an absolute value graph starts at (0, 0) and goes down and to the left through (negative 4, negative 2).

Step-by-step explanation:

The range of the graph is all real numbers greater than or equal to 0.

9 0
3 years ago
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X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
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