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densk [106]
3 years ago
9

Round each approximate answer to three decimals 2a+1=-squat root 7

Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0
2a+1=sq r of 7=49
 2(24)=49
hope it helps

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14-12x+39x-18x=256-60x-657x​
emmasim [6.3K]

Answer:

\boxed{\bold{x=\frac{1}{3}}}

Step-by-step explanation:

Combine Similar Elements: \bold{-12x+39x-18x=9x}

\bold{14+9x=256-60x-657x}

Combine Similar Elements: \bold{-60x-657x=-717x}

\bold{14+9x=256-717x}

Subtract 14 From Both Sides

\bold{14+9x-14=256-717x-14}

Simplify

\bold{9x=-717x+242}

Add \bold{717x} To Both Sides

\bold{9x+717x=-717x+242+717x}

Simplify

\bold{726x=242}

Divide Both Sides By \bold{726}

\bold{\frac{726x}{726}=\frac{242}{726}}

Simplify

\bold{x=\frac{1}{3}}

4 0
4 years ago
How can you get coefficients that are equal for X?<br> 3x + 2y = 12<br> 6x + 3y = 21
Verizon [17]

Step-by-step explanation:

To make the coefficient of x equal we can multiply both sides of (1) by 2. the answer is B

5 0
3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
Read 2 more answers
Charles drew a plan for a rectangular piece of
dalvyx [7]

The fourth coordinate of rectangular piece of material is (2.8 , -2.7)

According to the question,

Charles drew a plan for a rectangular piece of material that he will use for a blanket. Three of the vertices are (-1.4, -2.7), (-1.4,3.7), and (2.8,3.7).

As we know , the opposite sides of rectangle are equal

If we locate these coordinates in our graph and join them

Length of rectangle will be = 2.8+1.4 = 4.2cm

Breadth of rectangle will be = 3.7 + 2.7 = 6.4cm

So, the fourth coordinate should lie 6.4cm far from  (2.8,3.7)

Subtracting 6.4 from y-axis,

Fourth coordinate = 3.7 - 6.4

= -2.7

Therefore , The fourth side of rectangle = (2.8 , -2.7)

To know more about Rectangle here

brainly.com/question/14207995

#SPJ1

4 0
1 year ago
A shipment contains 9 igneous, 7 sedimentary, and 7 metamorphic rocks. If 7 rocks are selected at random, find the probability t
yKpoI14uk [10]

Answer:

75 percent

Step-by-step explanation:

see the thing is

7 0
2 years ago
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