Answer:
A) The best way to picture this problem is with a probability tree, with two steps.
The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.
The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.
If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.
If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.
B) So a person can have a red marble and a blue marble in two ways:
1) Picking the red first and the blue last
2) Picking the blue first and the red last
C) P(R&B) = 3/5 = 60%
Step-by-step explanation:
C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5
Since it starts with 2 envelopes, subtract 2 from 17 to get how many and in all 3 packs.
17 - 2 = 15
Now, we divide that number by 3 to get how many are in each envelope.
15 / 3 = 5
There are 5 envelopes in each pack.
Answer:
for four right angles, should be only square.
for all sides congruent, square and rhombus
for 2 pairs of parallel sides, parallelogram and rhombus and square.
for only 1 pair of congruent sides, parallelogram and rhombus
Step-by-step explanation: doggo has asian smarts, not bsian
The new equation after shifting will be:
Step-by-step explanation:
Function trnafomations upward and left are defined as:
Upward:
f(x) => f(x)+b where b is an integer
Left:
f(x) => f(x+b) where b is an integers
Given function is:
Shifting the function 5 units left
Shifting the function upward 2 units
So,
The new equation after shifting will be:
Keywords: Functions, shifting
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