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Tpy6a [65]
3 years ago
8

During a single day at radio station WMZH, the probability that a particular song is played is 6/7. What is the probability that

this song will be played on at least 5 days out of 6 days? Round your answer to the nearest thousandth.
Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

The required probability is 0.462.

Step-by-step explanation:

Probability to play the song = 6/7

Probability not to play the song = 1 - 6/7 = 1/7

Required probability  

= Probability to play 5 days x probability not to play 1 one + Probability to play 6 days

=\left (\frac{6}{7}  \right ) ^5\times \frac{1}{7} + \left (\frac{6}{7}  \right ) ^6\\\\= \frac{6^5 +6^6}{7^6}\\\\=0.462

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A rectangle has an area of 12y^2+21y^512 y 2 +21y 5 12, y, squared, plus, 21, y, start superscript, 5, end superscript.The width
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Answer:

<em>Width</em>: 3y²

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12y² = 3y²*4

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8 0
3 years ago
The polynomial $f(x)$ has degree 3. If $f(-1) = 15$, $f(0)= 0$, $f(1) = -5$, and $f(2) = 12$, then what are the $x$-intercepts o
Alex_Xolod [135]

Your calculator's cubic regression function can tell you the equation is

... f(x) = 2x³ + 5x² -12x = x(x +4)(2x-3)

The x-intercepts are -4, 0, +1.5.

_____

If you want to solve this "by hand", you can first of all recognize that since there is an x-intercept at 0, the cubic will only have three coefficients. That is, you can write the equation as

... f(x) = ax³ + bx² + cx

Substituting the given points (except (0, 0)) gives three linear equations in a, b, c.

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... a + b + c = -5 . . . . for x=1

... 8a +4b +2c = 12 . . for x=2

adding the first two equations gives 2b=10, or b=5. Now, you can reduce the system to

... a + c = -10

... 4a +c = -4

Subtracting the first of these equations from the second gives 3a=6, or a=2. That tells you c=-12 (from a+c=10).

Then your equation is

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Factoring by any of the usual techniques, or graphing, or using the quadratic formula will tell you the zeros (x-intercepts) are as above.

_____

Since the input values are sequential, you can also develop the function from differences of the output values. Those are 15, 0, -5, 12. First differences are -15, -5, +17. Second differences are +10, +22. The third difference is 12. Using the first of these differences in appropriate places in the interpolating polynomial formula, we have

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3 years ago
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