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Tpy6a [65]
2 years ago
8

During a single day at radio station WMZH, the probability that a particular song is played is 6/7. What is the probability that

this song will be played on at least 5 days out of 6 days? Round your answer to the nearest thousandth.
Mathematics
1 answer:
Vlad [161]2 years ago
4 0

Answer:

The required probability is 0.462.

Step-by-step explanation:

Probability to play the song = 6/7

Probability not to play the song = 1 - 6/7 = 1/7

Required probability  

= Probability to play 5 days x probability not to play 1 one + Probability to play 6 days

=\left (\frac{6}{7}  \right ) ^5\times \frac{1}{7} + \left (\frac{6}{7}  \right ) ^6\\\\= \frac{6^5 +6^6}{7^6}\\\\=0.462

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Find the surface area of a cone if the diameter of its base is 13.5 feet, and it has a slant height of 16.8 feet. Round to the n
Tresset [83]

The diameter is given which is 13.5feet and radius is half of diameter. Therefore radius = 6.75 feet.

Slant height = 16.8 feet

The formula of surface area of cone is

S = \pi *r(r+l) \\ S = \pi*6.75(6.75+16.8) \\ S =\pi*6.75*23.55 = 499.2 ft^2

Correct option is C

5 0
3 years ago
A sweater is 65% wool by weight. If the sweater weighs 12.4 ounces how many ounces of wool is the sweater?
Mashutka [201]

Answer:

8.06 ounces

Step-by-step explanation:

Ounces of wool of the sweater = percent of wool in the sweater x weight of the sweater

65% x 12.4 ounces

0.65 x 12.4 = 8.06 ounces

6 0
3 years ago
20186<br> What is the answer
Wewaii [24]

Answer:

is that a real eqasion??

Step-by-step explanation:

20186

7 0
3 years ago
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Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long
Ne4ueva [31]

We are given

Jim's backyard:

Length is

L=15\frac{5}{6} =\frac{95}{6} yards

width is

W=10\frac{2}{5} =\frac{52}{5} yards

Since, this is rectangle

so, we can find area of rectangle

A=L*W

A=(\frac{95}{6})*(\frac{52}{5})

A=\frac{494}{3} yard^2

Area of one sod:

length is

l=1\frac{1}{3} =\frac{4}{3} yards

width is

w=1\frac{1}{3} =\frac{4}{3} yards

Since, it is rectangle in shape

so,

Area=l*w

A=\frac{4}{3}*\frac{4}{3}

A=\frac{16}{9}yard^2

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

N=\frac{\frac{494}{3} }{\frac{16}{9} }

now, we can simplify it

N=\frac{741}{8} pieces need ..............Answer

7 0
3 years ago
Calculate the number of subsets and the number of proper subsets for the set.
arlik [135]

A set of n elements has 2ⁿ subsets. One of these subsets is the set itself, so this set would have 2ⁿ - 1 <em>proper</em> subsets.

The given set has 4 elements, so it has 2⁴ = 16 subsets and 2⁴ - 1 = 15 proper subsets.

Just to illustrate the claim, we have

• subsets of size 0 (1 of these):

{ } (empty set)

• subsets of size 1 (4 of these):

{1/6}, {1/7}, {1/8}, {1/9}

• subsets of size 2 (6 of these):

{1/6, 1/7}, {1/6, 1/8}, {1/6, 1/9}, {1/7, 1/8}, {1/7, 1/9}, {1/8, 1/9}

• subsets of size 3 (4 of these):

{1/6, 1/7, 1/8}, {1/6, 1/7, 1/9}, {1/6, 1/8, 1/9}, {1/7, 1/8, 1/9}

• subsets of size 4 (1 of these):

{1/6, 1/7, 1/8, 1/9}

and the last one is the only subset that is not a proper subset, because that subset = the set.

6 0
2 years ago
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