3 years ago

Find the recursive definition for this sequence 2,6,18,54,162

Mathematics

1 answer:

Rudiy273 years ago

8 0

Each number is multiplied by 3 to get to the next. Think about how you get from the number to the next, and so on.

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What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – StartRoot StartFraction 11 Over 2 EndFraction EndRoot

Phantasy [73]

Answer:

The zeros are

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

Step-by-step explanation:

we have

$f(x)=2x^{2}+8x-3$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

Equate the function to zero

$2x^{2} +8x-3=0$

$a=2\\b=8\\c=-3$

substitute in the formula

$x=\frac{-8\pm\sqrt{8^{2}-4(2)(-3)}} {2(2)}$

$x=\frac{-8\pm\sqrt{88}} {4}$

$x=\frac{-8\pm2\sqrt{22}} {4}$

$x=-2\pm\frac{\sqrt{22}}{2}$

therefore

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

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Find the recursive definition for this sequence 2,6,18,54,162​

Find the recursive definition for this sequence 2,6,18,54,162