Answer: Q=1/2p+15,= p=2q-30= Slope = 1.000/2.000 = 0.500
p-intercept = -30/1 = -30.00000
q-intercept = 30/2 = 15
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
p-(2*q-30)=0
Solve p-2q+30 = 0
we have an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.
In this formula :
y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the line properties. We shall now graph the line p-2q+30 = 0 and calculate its properties
Notice that when p = 0 the value of q is 15/1 so this line "cuts" the q axis at q=15.00000
q-intercept = 30/2 = 15
When q = 0 the value of p is -30/1 Our line therefore "cuts" the p axis at p=-30.00000
p-intercept = -30/1 = -30.00000
Slope is defined as the change in q divided by the change in p. We note that for p=0, the value of q is 15.000 and for p=2.000, the value of q is 16.000. So, for a change of 2.000 in p (The change in p is sometimes referred to as "RUN") we get a change of 16.000 - 15.000 = 1.000 in q. (The change in q is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)
Slope = 1.000/2.000 = 0.500
Answer: $300
Step-by-step explanation:
Mr. Calvin earned 
He spent
on food i.e.



Remaining money = 
So, he saved $300 after expenses
1 clipe..............7/8
x.......................56
7x/8 = 56
7x = 56*8
x = 56*8/7
x = 8*8
x = 64 clipes
1 clipe = 0,03
64 clipes = 0,03*64
64 clipes = 1,92
Answer:
9/5 = 1.8
All you have to do is divide the numerator by the denominator.
Hope this helps!
-Mikayla
Answer:
Rational
Step-by-step explanation:
Because it's an actual number that you can graph where irrational would be is if it would be a number that like pie or something where it just goes on and on