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Inessa [10]
3 years ago
7

1.)Solve the following equation by completing the square

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0
Okay so for number 1 is x = -28
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Help Me Please! I will give you 5 stars if your answer is correct
andrey2020 [161]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Describe and correct the error in finding the sum. -5/8 + 1/8 = -5+1/8 = -6/8 = -3/4
Sav [38]

Answer:  -1/2 is the correct answer

Step-by-step explanation:

(-5/8)+(1/8)

=((-5+1)/8)

= -4/8

=-1/2

8 0
3 years ago
Benny opened a bank account. He deposited $92.50 into his account every month for 10 months. He used $36.50 every month to pay f
neonofarm [45]
$92.50 * 10 =$925 ( deposited$92.50 into his account every month for 10 so we multiply)
$36.50*10 = $365 ( used $36.50 every month to pay art lessons every month means he took out)
925-365=560 ( total amt left in the account after taking out $365)
He used 1 over 2 of total money means
560/2 = 280

The answer would be B $280.

Hope this helps!!
6 0
3 years ago
Find the intervals on which f(x)=2xx2+64 increases.
Shtirlitz [24]

f(0)=64, f(1)=66, f(2)=72, f(3)=82, f(4)=96,...=2,6,10,14,...=2{1,3,5,7,...}
This can be written 2{2x+1}, so the intervals on which f(x) increases are 4x+2.
4 0
3 years ago
The product of two numbers is 48. The first number is positive, and the second is four more than twice the first number. Find th
lukranit [14]
The first number is positive, so the second has to be positive too so that their product can be a positive number which is 48.
Suppose the first number is x and the second number is y.
We know that:
y = 4 + 2x (4 more meaning adding 4 to sthing and that sthing is twice x hence the 2x)
Moving on, we have x.y = 48 (we replace y by its other value that has x in it so that we have only one unknown variable that we need to find)
                        <=> x.(4 + 2x) = 48
                        <=> 4x + 2x^2 = 48
                        <=> 2x^2 + 4x - 48 = 0 (we add (-48) on both sides)
Now we have to solve the second degree equation, I don't know the exact names of things since I didn't study math in English, but we have to calculate the value of, say, b^2 - 4ac (ax^2 + bx + c)
in this case b = 4 , a = 2, c = -48
so b^2 - 4ac = 16 + 384 = 400, so the square root of that equals 20
now, we have two possible values for x, suppose x1 and x2
x1 = (-4 + 20)/2.a = (-4 + 20)/4 = 16/4 = 4
x2 =  (-4 - 20)/2.a = (-4 - 20)/4 = (-24)/4 = (-6) (which is impossible giving that the two numbers must be positive)
So x has to be equal to x1 => x = 4
We find x, and since y = 4 + 2x <=> y = 4 + 2.4 = 4 + 8 = 12
As a conclusion, x = 4 , y = 12 
6 0
3 years ago
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