<em><u>The least amount of money you would need to invest per month is; $335</u></em>
<em><u>The anticipated rate of return on your investments is; 7%</u></em>
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- Amount to have been saved at the end of 10 years ≥ $40,000
Number of years of savings = 10 years.
- We want to find out the least amount to be invested per month.
There are 12 months in a year. Number of months in 10 years = 10 × 12 = 120 months.
- Thus, amount to be saved monthly = 40000/12 = $333.33
- Since the minimum amount he wants to save after 10 years is $40000, then we need to approximate the monthly savings in order.
Thus;
Monthly savings ≈ $335
- Now, for the anticipated rate of return on the investment, we know from S & P's that the benchmark on good rate of return for investment is a minimum of 7%.
- From online calculator, the worth of the investment after 10 years based on 7% rate of return yearly would be $57626.
Read more at; brainly.com/question/9187598
Answer:
Step-by-step explanation:
6.
P(even)=4/8=1/2
=50 %
7.
P(8)=23/50
=46 %
p(the person does not use any facility)= 59/130
If we are to write this equation in slope-intercept form, it will be in y = mx + b, where m is the slope of the line and b is the y intercept. We need then to find the slope of the line using 2 points on the line and filling in the slope formula to find the slope. One of the points we can use is (0, 3) which is also the y intercept. The y-intercept is found where x = 0. Where x = 0, y = 3. So b = 3. Now for the slope we will use (0,3) and (4,4):
. Using that m value and that b value we have the equation
. There you go!
Answer:
500=120+60
Variable would either be M or D For 60
Step-by-step explanation:
