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3 years ago

Simplify this expression.

Mathematics

1 answer:

amm18123 years ago

7 0

Answer: 0.88

Step-by-step explanation:

Okay -5.37 + 8.14 = 2.77 ( you can simply plug this into the calculator or you could switch the problem around so it’s 8.14 - 5.37, either way you’ll get 2.77)

And then you take 2.77 -1.89 = 0.88

So 0.88 is your answer

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A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A

Zigmanuir [339]

Answer:

The probability that all 4 selected workers will be from the day shift is, = 0.0198

The probability that all 4 selected workers will be from the same shift is = 0.0278

The probability that at least two different shifts will be represented among the selected workers is = 0.9722

The probability that at least one of the shifts will be unrepresented in the sample of workers is P(A∪B∪C) = 0.5256

Step-by-step explanation:

Given that:

A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A quality control consultant is to select 4 of these workers for in-depth interviews:

The number of selections result in all 4 workers coming from the day shift is :

$(^n _r) = (^{10} _4)$

$=\dfrac{(10!)}{4!(10-4)!}$

= 210

The probability that all 5 selected workers will be from the day shift is,

$\begin{array}{c}\\P\left( {{\rm{all \ 4 \ selected \ workers\ will \ be \ from \ the \ day \ shift}}} \right) = \frac{{\left( \begin{array}{l}\\10\\\\4\\\end{array} \right)}}{{\left( \begin{array}{l}\\24\\\\4\\\end{array} \right)}}\\\\ = \frac{{210}}{{10626}}\\\\ = 0.0198\\\end{array}$

(b) The probability that all 4 selected workers will be from the same shift is calculated as follows:

P( all 4 selected workers will be) $= \dfrac{ (^{10}_4) }{(^{24}_4)}+\dfrac{ (^{8}_4) }{(^{24}_4)} + \dfrac{ (^{6}_4) }{(^{24}_4)}$

where;

$(^{8}_4) } = \dfrac{8!}{4!(8-4)!} = 70$

$(^{6}_4) } = \dfrac{6!}{4!(6-4)!} = 15$

∴ P( all 4 selected workers is ) $=\dfrac{210+70+15}{10626}$

The probability that all 4 selected workers will be from the same shift is = 0.0278

P ( at least two different shifts will be represented among the selected workers) $= 1-\dfrac{ (^{10}_4) }{(^{24}_4)}+\dfrac{ (^{8}_4) }{(^{24}_4)} + \dfrac{ (^{6}_4) }{(^{24}_4)}$

$=1 - \dfrac{210+70+15}{10626}$

= 1 - 0.0278

The probability that at least two different shifts will be represented among the selected workers is = 0.9722

(d)What is the probability that at least one of the shifts will be unrepresented in the sample of workers?

The probability that at least one of the shifts will be unrepresented in the sample of workers is:

$P(AUBUC) = \dfrac{(^{6+8}_4)}{(^{24}_4)}+ \dfrac{(^{10+6}_4)}{(^{24}_4)}+ \dfrac{(^{10+8}_4)}{(^{24}_4)}- \dfrac{(^{6}_4)}{(^{24}_4)}-\dfrac{(^{8}_4)}{(^{24}_4)}-\dfrac{(^{10}_4)}{(^{24}_4)}+0$

$P(AUBUC) = \dfrac{(^{14}_4)}{(^{24}_4)}+ \dfrac{(^{16}_4)}{(^{24}_4)}+ \dfrac{(^{18}_4)}{(^{24}_4)}- \dfrac{(^{6}_4)}{(^{24}_4)}-\dfrac{(^{8}_4)}{(^{24}_4)}-\dfrac{(^{10}_4)}{(^{24}_4)}+0$

$P(AUBUC) = \dfrac{1001}{10626}+ \dfrac{1820}{10626}+ \dfrac{3060}{10626}-\dfrac{15}{10626}-\dfrac{70}{10626}-\dfrac{210}{10626} +0$

The probability that at least one of the shifts will be unrepresented in the sample of workers is P(A∪B∪C) = 0.5256

5 0

3 years ago

What is the area of the base of the cone below? Round the answer to the nearest tenth if necessary. A cone with height 8 inches

docker41 [41]

Answer:

The area of the circle is 19.5 in²

Step-by-step explanation:

First of all to solve this problem we have to know the formula to calculate the volume of a cone

v = volume = 52 in³

r = radius

h = height = 8 in

π = 3.14

v = 1/3 * π * r² * h

we solve r

3 * v /h * π = r²

we replace the known values

3 * 52 in³ / 3.14 * 8 in = r²

156 in³ / 25.12 in = r²

6.21 in² = r²

√6.21 in² = r

2.49 in = r

now that we have the radius we need to use the area formula of a circle:

a = area

r = radius = 2.49 in

π = 3.14

a = π * r²

we replace the known values

a = 3.14 * (2.49 in)²

a = 3.14 * 6.21 in²

a = 19.5 in²

The area of the circle is 19.5 in²

7 0

3 years ago

Read 2 more answers

3 raise to power x equal to -3

cluponka [151]

3 ^x = -3

then, x would be -1

6 0

3 years ago

Solve for B in the picture below

Oxana [17]

Answer:

b= -48

Step-by-step explanation:

by transposing,

43=59+b/3

b/3+59=43

b/3=43-59

b/3= -16

b= -16×3

b= -48

therefore the answer is b= -48

hope it helps!!!

PLEASE MARK BRAINLIEST..

5 0

2 years ago

Read 2 more answers

Will give brainlst Have a nice day

il63 [147K]

Answer and Step-by-step explanation:

The answer is 5 units.

This is because the slope of that line is 2.5, and diagonal 2.5 units twice.

#teamtrees #PAW (Plant And Water)

8 0

3 years ago