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prohojiy [21]
3 years ago
15

. Joe worked on his science project 4 2/3 hours on Saturday, 3.5 hours on Monday, and 3 hours on Tuesday. What was the total num

ber of hours he worked on his science project?
Mathematics
1 answer:
boyakko [2]3 years ago
5 0
The answer is 10 hours and 20 minutes
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The sales at Marty's Meat Market increased from $130,000 per month to $136,500. Determine the percent increase.
kicyunya [14]
Hello! For this question, we are looking for the percent of change. The formula for percent of change is change/original = x/100, where change is tge difference between two numbers, and the original is the previous number. 136,500 - 130,000 is 6,500. The original number is 130,000. It would be set up like this:

6,500/130,000 = x/100

Let's cross multiply the values. 6,500 * 100 is 650,000. 130,000 * x is 130,000x. That makes 650,000 = 130,000x. Now, divide each side by 130,000 to isolate the x. 130,000x/130,000 cancels out. 650,000/130,000 is 5. There. x = 5% increase. The answer is A: 5%.
8 0
4 years ago
Please solve this for me!
Slav-nsk [51]

Answer:

  y = -1/6x +2

Step-by-step explanation:

The black vertical line in the middle of the graph is the y-axis. The blue line crosses it a the point marked 2. This is known as the y-intercept.

The slope of the line is the ratio of "rise" (vertical change) to "run" (horizontal change).

There is a marked point on the line at the y-intercept, where x=0 and y=2. There is another marked point to the right of that, where x=6 and y=1.

The vertical change between those two points is 1 -2 = -1.

The horizontal change between those two points is 6 -0 = 6

The slope is then -1/6.

__

The slope-intercept form of the equation of a line is often written as ...

   y = mx + b

where "m" is the slope (-1/6), and "b" is the y-intercept.

Using the values we found above, the equation of the line is ...

  y = -1/6x +2

5 0
3 years ago
3. If mZEFH = (5x + 1), mZHFG = 62°, and<br> mZEFG = (18x + 11), find each measure.
arsen [322]

Answer/Step-by-step explanation:

Given:

m<EFH = (5x + 1)°

m<HFG = 62°

m<EFG = (18x + 11)°

Required:

1. Value of x

2. m<EFH

3. m<EFG

SOLUTION:

1. Value of x

m<EFH + m<HFG = m<EFG (angle addition postulate)

(5x + 1) + 62 = (18x + 11)

Solve for x using this equation

5x + 1 + 62 = 18x + 11

5x + 63 = 18x + 11

Subtract 18x from both sides

5x + 63 - 18x = 18x + 11 - 18x

-13x + 63 = 11

Subtract 63 from both sides

-13x + 63 - 63 = 11 - 63

-13x = -52

Divide both sides by -13

-13x/-13 = -52/-13

x = 4

2. m<EFH = 5x + 1

Plug in the value of x

m<EFH = 5(4) + 1 = 20 + 1 = 21°

3. m<EFG = 18x + 11

m<EFG = 18(4) + 11 = 72 + 11 = 83°

8 0
4 years ago
Ramon and justine are both watching brodcast both star at 7:00 a.M and ends at 9:00 a.M one one shows commercials every 17 minut
hoa [83]

Answer:

<h2>1:58 minutes after the show</h2>

Step-by-step explanation:

Step one:;

given data

start time= 7:00 am

end time= 9:00 am

we are told that one broadcast shows commercial every 17minutes

and the other shows commercials every 14 minutes

now the time when they both sho commercial is given by the greates common multiple of the times 17 and 14

multiples of  17= 17,34,51,68,85,102,119,136,153,170,187,204,221,238

multiples of  14= 14,28,42,56,70,84,98,112,126,140,154,168,182,196,210,224,238

for the number above 238 is common to both

238minutes to hours= 3.96667

=3:58 minutes

this shows that commercials will show at the same time 1:58 minutes after the show

4 0
3 years ago
Nathan has 80 stamps in his collection. He adds 1 stamp to it today. Each day he plans to add twice the number of stamps as the
Dafna11 [192]
We start with 80 and we add 1 on the first day, 2 on the 2nd, 4 on the 3rd, etc.. Looking at the numbers being added 1 = 20 2 = 21 4 = 22 8 = 23 16 = 24 . . . We start with 80 and we add 2n to it where n represents the number of days into the iteration with n starting at 0 The function that shows how many stamps we have on any given day is D S = 80 + ∑ 2n Where D is the number of days we are into the iteration n=0 NOTE: This starts at day 0 which would be S = 80 + 20 = 80 + 1 = 81 stamps Example: To find how many stamps we have on D = 4 we would have S = 80+20+21+22+23+24 = 80+1+2+4+ 8+16 = 111 stamps
6 0
3 years ago
Read 2 more answers
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