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2 years ago

Simplify. Consider all the cases. |7-(12-x)|

Mathematics

1 answer:

Phantasy [73]2 years ago

5 0

Answer: |x-5|

Step-by-step explanation:

I dont know how to exlplain it

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4 1/3 divided 5 1/6<br> Please help me!

Effectus [21]

Answer:

6/31

Step-by-step explanation:

4 1/3 ➡ 13/3

5 1/6 ➡ 31/6

to divide two rational expression you should turn the second number upside-down(finding its reciprocal) then multiply them :

13/3 × 6/31 = 26/31

8 0

2 years ago

I need two equations to use elimination but I don't know what equations to use.

lyudmila [28]

2x+3y=160
-2x+7y=25 I hope that helps!!

7 0

2 years ago

Read 2 more answers

Need help on this please

VladimirAG [237]

Awnser: 1/9

Hope ir helps! :D

1-1 = 0

12-6 = 6

0+1 = 1

6 +3 = 9

1/9!!!

5 0

3 years ago

Kim rode her bicycle 135 miles in 9 weeks riding the same distance each week. Eric rode his bicycle 102 miles in 6 weeks, riding

IgorLugansk [536]

The correct answer is @, because Kim rode15 miles per week, and Eric rode 17 per week

8 0

3 years ago

Read 2 more answers

Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp

romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

$\text{Distance}=\text{Speed}\times \text{Time}$

$\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}$

$\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}$ .

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

$\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}$

$\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}$

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

$\text{Distance between both cars}=\sqrt{147^2+150^2}$

$\text{Distance between both cars}=\sqrt{21609+22500}$

$\text{Distance between both cars}=\sqrt{44109}$

$\text{Distance between both cars}=210.021427\approx 210$

Therefore, the both cars will be 210 miles apart and option C is the correct choice.

3 0

3 years ago