Question

Please explain how you got your answer, I don't quite understand how to do this.

Answer 1

Question :-

Solve for y in the two equations below using substitution.

• 2x - 8y = 6
• -2x + 2y = 7

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Solution :-

Given Information :-

• Equation 1 ➢ 2x - 8y = 6
• Equation 2 ➢ -2x + 2y = 7

To Find :-

• Solve for y in the two equations.

Calculation :-

Equation 1 ➢ 2x - 8y = 6

Equation 2 ➢ -2x + 2y = 7

Adding both equations together, by combining similar terms, We get,

• 2x + -2x = 0
• -8y + 2y = -6y
• 6 + 7 = 13

When we combine the terms, We get,

⇒ -6y = 13

Now, solving for y, by divide Right Hand Side & Left Hand Side by -6, We get,

⇒ y = $\sf \frac{13}{-6}$

⇒ y = $\sf \frac{-13}{6}$

∴ The value of y is $\bf \frac{-13}{6}$

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Final Answer :-

The value of y is $\bf \frac{-13}{6}$

Hence, Option C. $\bf \frac{-13}{6}$ is correct answer.

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Answer 2

2x - 8y = 6

-2x + 2y = 7

Add the two equations together by combining like terms:

2x + -2x = 0

-8y + 2y = -6y

and 6 + 7 = 13

So when you combine the terms you end up having:

-6y = 13

Now solve for y by dividing each side by -6:

y = 13/-6

Rewrite by moving the negative sign in front of the fraction to get

y = -13/6

The answer is C.