I=P*R*T
I=1000*.05*5
She will pay $250.
Answer:
the answer??????
Step-by-step explanation:
Answer:
19/24
Step-by-step explanation:
z-2/3=1/8
z=2/3+1/8
z=19/24
P=2L+2W
1. Subtract 2L from both sides
P-2L=2W
2.Divide both sides by 2 to isolate "W"
P-2L/2=W
3.Flip the equation
W=P-2L/2
So solution is
W=P-2L/2
Answer: Population has a standard deviation of 32. What is the standard error f the sampling distribution if the sample size is 100?
Step-by-step explanation: Here we are told that a population has a standard deviation of 32 and that we have a sample of size 100 from this population that are asked for the standard error of the sampling distribution. Now it would be important to know what statistic we are taking from these samples. Now we would need to know what what statistic we're taking from these samples. Um I'm assuming that we're talking about sample averages in this case the standard error is well, let's sample averages are just distributed like this. They are so we have anna's big, which means that our sample averages are going to be approximately normally distributed. The mean of the sample averages will be equal to the mean of the population, and the standard air of the sample averages will be equal to the population. Standard deviation divided by the square root of the sample size. So this is our standard error of the sampling distribution, And so this is equal to 3.2. So that is your answer. That is the standard error of the sampling distribution. When the sample size is 100 is 32 I hope that helped
