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2 years ago

Solve for x.

Mathematics

1 answer:

Doss [256]2 years ago

5 0

Answer:

x= 16

Step-by-step explanation:

First, you want to distribute each side! (you're gonna wanna learn this because you will be having to do it for the next 3 years no joke it sucks)

7(x+2) can be distributed as 7x+14 after multiplying 7 times x and 7 times 2, and 6(x+5) can be distributed as 6x+30.

Now, you have to get the x on one side to solve for x (so like x=__).

To do this, look at the equation as of now. 7x+14=6x+30.

We can minus 14 and bring that to the right, and minus 6x and bring that to the left to separate the x's and the regular numbers.

Now we have 16=x (or x=16).

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Duval County Landscaping uses two different sized trucks to deliver mulch. The first truck can transport x cubic yards of mulch,

Gre4nikov [31]

For this case, the first thing we must do is define variables.
We have then:
x: number of cubic yards of mulch that first truck can transport
y: number of cubic yards of mulch that second truck can transport
Now we write the expression.
The first truck makes 12 trips to a job site:
$12x
$
The second makes 14 trips:
$14y
$
The difference between the first truck and the second truck is:
$12x - 14y$
Answer:
An expression that represents the difference in the total number of cubic yards that the first truck delivers compared to the second is:
$12x - 14y$

8 0

2 years ago

Read 2 more answers

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$