All categories

3 years ago

Solve for x 2x+16 X+16

Mathematics

2 answers:

Sati [7]3 years ago

7 0

JL = x+16

JK+KL = x+16

2x+16+7 = x+16

2x+23 = x+16

2x-x = 16-23

x = 7

nydimaria [60]3 years ago

3 0

Answer:

2x(16)+16(16)

32x+256

32x/32=256/32

x=8

You might be interested in

What is the smallest value of n such that an algorithm whose running time is 100n 2 runs faster than an algorithm whose running

Semmy [17]

Answer:

n = 15

Step-by-step explanation:

For inputs of the value of n, the running time for the algorithm A is 100n^2 and that of B is 2^n.

If A is to run faster than B, 100n^2 must be smaller than 2^n.

Let's check from n = 1 to know the value of n that fits

n = 1

100(1)^2 > 2^1

100 > 2

n = 2

100(2)^2 > 2^2

400 > 4

n = 4

100(4)^2 > 2^4

1600 > 16

n = 8

100(8)^2 > 2^8

6400 > 2^8

n = 16

100(16)^2 < 2^16

25600 < 2^16

This implies that between n = 8 and 16, A starts to run faster than B

n = (8+16)/2 = 12

100(12)^2 > 2^12

14400 > 2^12

n = (12+16)/2 = 14

100(14)^2 > 2^14

19600 > 2^14

n = (14+16)/2

n = 15

100(15)^2 < 2^15

22500 < 2^15

At n= 15, A starts running faster than B

8 0

3 years ago

jakes map shows the distance from the bake stars cafe to the restaurant supply store as 3 centimeters. if the scale of the map i

Mila [183]

Answer:

It would be 24 kilometers.

Step-by-step explanation:

This is because 1 centimeter on the map equals 8 kilometers in real life.

Since the cafe's distance is 3 centimeters, it would be 24 kilometers.

3 * 1 = 3 centimeters

3 * 8 = 24 kilometers

6 0

4 years ago

A lamp post 15 feet high casts a shadow

miv72 [106K]

Here you go! I decided to write it down for you. Sorry for the bad handwriting! :)

8 0

3 years ago

Figure out the number combination. WIll choose brainliest.

strojnjashka [21]

Answer: Combination: 9636

Step-by-step explanation: Combine the numbers of each section without going past the number 9

8 0

2 years ago

The number of students who attended FPM in 2015 was 1380. In 2016, 1405 students attended FPM. what was the percent of change in

Fittoniya [83]

The percent of change in student enrollment is 1.81 % increase

Solution:

Given that, The number of students who attended FPM in 2015 was 1380

In 2016, 1405 students attended FPM

To find: Percent change

The percent change is given by formula:

$\text { percent change }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100$

If the result is positive, it is percent increase

If the result is negative, it is percent decrease

From given,

Initial value in 2015 = 1380

Final value in 2016 = 1405

Substituting the values in formula, we get

$\text { percent change }=\frac{1405-1380}{1380} \times 100\\\\\text { percent change }=\frac{25}{1380} \times 100\\\\\text { percent change }= 0.01811 \times 100\\\\\text { percent change }= 1.81$

Thus percent of change in student enrollment is 1.81 % increase

6 0

3 years ago