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Umnica [9.8K]
3 years ago
7

Please help due in 5 minutes

Mathematics
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

x = 0

y= -3

Step-by-step explanation:

x = y + 3 into the equation y = -4x - 3, so

y = -4(y+3) - 3

y = -4y - 12 - 3

y = -4y - 15

5y = -15

y = -3

Then, you can substitute this into the equation x = y + 3

x = -3 + 3\\x = 0

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Write2.1 as a mixed number and as an improper fraction.<br> Do not try to simplify your answers.
Elden [556K]

Answer:

2 1/10 and 21/10

Step-by-step explanation:

2.1 is 2 + 0.1 when expanded.

2 is just 2 and then 0.1 as a fraction is 1/10. The mixed number would be                 2 1/10.

The improper fraction  is just 21/10 (convert the mixed number into improper form).

Converting from mixed number to improper: <u>Multiply the number in the front (in this case 2) by the denominator. </u>

<u />

<u>That is 2 x 10 which is 20. Then add that number (20) to the numerator. 20 + 1 is equal to 21. </u>

<u />

<u>21 would be our numerator and the denominator would stay the same (10). </u>

21/10 is the improper form.

8 0
2 years ago
Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)
JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence  : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

a=46\\d=42-46=-4

So , Let's calculate how many terms are there as :

⇒ a_n=a +(n-1)d

⇒ -450=46 +(n-1)(-4)

⇒ -496=(n-1)(-4)

⇒ \frac{-496}{-4}=n-1

⇒ 124=n-1

⇒ n=125

Sum of an AP is :

⇒ S_n = \frac{n}{2}(2a+(n-1)d)

⇒ S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))

⇒ S_1_2_5 = \frac{125}{2}(-404)

⇒ S_1_2_5 =-25,250

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

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3 years ago
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Answer is B- you might begin to visualize the story.

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Answer:

c.2,400 I think is c. nose you

Step-by-step explanation:

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A bag of candy contains 300 pieces of which 28% are red. How many are not red?
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