Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = 
~ N(0,1)
where, 
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( > 
) = P(Z > 1.25) = 1 - P(Z 
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
16^6
Step-by-step explanation:
4^2 x 4^4 = 16^6
Answer is d, you can see the graph touches the x line in the point 5 so the answer is (5,0)
Answer:
3.2*10^8>1.2*10^8>7*10^5>5*10^3
Step-by-step explanation:
5*10^3 = 5000
3.2*10^8=320000000
1.2*10^8=120000000
7*10^5=700000
320000000>120000000>700000>5000
therefor
3.2*10^8>1.2*10^8>7*10^5>5*10^3
Answer:
h=48
Step-by-step explanation:
You should create an even proportion. So you could do seconds over heartbeats or the other way around. I decided to do the other way around. Since yu want to see h in m minutes and in a minute there are 60 seconds, I did 8/10 = h/60. Instead of cross multiplying, I saw that 10 times 6 is 60 so 8 x 6=h. 8 x 6 = 48 so h=48.
