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3 years ago

Help meeeee plsssssssss

Mathematics

2 answers:

prisoha [69]3 years ago

5 0

Answer:

The Answer is D! :)

Step-by-step explanation:

Snowcat [4.5K]3 years ago

4 0

Answer:

Step-by-step explanation:

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Please help quickly AB=AD and BC=DC x=?

Arisa [49]

Answer:

x = 110

Step-by-step explanation:

measure of abd is 35, meaning adb is also 35.

so dab + abd + adb is 180

=> x + 35 + 35 = 180

=> x + 70 = 180

=> x = 180-70

=> x = 110

110 degrees is the value of x.

8 0

2 years ago

32) Find the value of 5x° + 2x-1 when x = 4.

SashulF [63]

Answer:

5x4°x7

Step-by-step explanation:

5x°+2x-1 when x =4

5x4°+2x4-1

5x4°+8-1

=5x4°x7

5 0

3 years ago

Factor: 4tan^2x-(4)/(cotx)+sinx(cscx) ...?

lisov135 [29]

4tan^(2)x-((4)/(cotx))+sinxcscx

Multiply -1 by the (4)/(cotx) inside the parentheses.

4tan^(2)x-(4)/(cotx)+sinxcscx

To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.

4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin...

Complete the multiplication to produce a denominator of cotx in each expression.

(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot...

Combine the numerators of all expressions that have common denominators.

(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)

8 0

3 years ago

What is the answer?

iVinArrow [24]

Answer:42

Step-by-step explanation:

7 0

3 years ago

At 7:00 p.m., there are 1,000 home-team fans and 700 away-team fans at a football game. After 7:00 p.m, 15 home team fans arrive

OleMash [197]

Answer:

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=109:67

Step-by-step explanation:

Initially , total home team fans =1000

and away team fans = 700.

7:00 pm to 8:00 pm = 1 hour = 60 minutes

Given that

Every 10 minutes the number of arrival home team fans is 15.

Then in 1 minutes the number of arrival home team fans is $\frac{15}{10}$

and in 60 minutes the number of arrival home team fans is $\frac{15 \times 60}{10}$

=90

Therefore total home team fans = (90+1000)=1090

Given that

Every 10 minutes 5 fans leave of away team leave.

then in 1 minutes $\frac{5}{10}$ fans leave of away team leave.

and In 60 minutes $\frac{5\times 60}{10}$ =30 fans leave of away team leave.

Since 30 away team fans leave.

Total away team fans = (700-30)=670

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=1090:670

=109:67

4 0

3 years ago