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Ket [755]
3 years ago
13

|x+10|, if x=-12 Ahhhh I'm not sure how to do this

Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

your answer is -2

Step-by-step explanation:

Hope helps

:3

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Y=-2x+4 y=6x+12 substitution method
sergey [27]

Answer:

x = - 1, y = 6

Step-by-step explanation:

Given the 2 equations

y = - 2x + 4 → (1)

y = 6x + 12 → (2)

Substitute y = 6x + 12 into (1)

6x + 12 = - 2x + 4 ( add 2x to both sides )

8x + 12 = 4 ( subtract 12 from both sides )

8x = - 8 ( divide both sides by 8 )

x = - 1

Substitute x = - 1 into either of the 2 equations and solve for y

Substituting into (2)

y = 6(- 1) + 12 = - 6 + 12 = 6

Solution is (- 1, 6 )

6 0
3 years ago
Figure A is a scale image of Figure B.<br><br> What is the value of x?
nasty-shy [4]

Answer:

5.4

Step-by-step explanation:

7.2/4 =1.8

3x1.8 = 5.4

6 0
3 years ago
eugheugh eughhhh I've been listening to my comfort playlist stressing about this test for too long Please just help ;-;
Kaylis [27]

Answer:

2 and 4 are correct

Step-by-step explanation:

1 is incorrect because 4/5 being bigger than 7/10

3 is incorrect because 2/3 is more than 5/9

6 0
3 years ago
15(d+7)=4(d-4)+11d answer? ​
Viktor [21]

Answer:

Step-by-step explanation:

Factor out to simplify:

15d+105=4d-16+11d

15d+105=15d-16

subtract 15d from both sides

105=-16

this means that there are no solutions for d

6 0
3 years ago
x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −
snow_tiger [21]
For this case, what we must do is fill squares in all the expressions until we find the correct result.
 We have then:
 
 x2 + y2 − 4x + 12y − 20 = 0 x2 + y2  − 4x + 12y = 20
 x2  − 4x + y2 + 12y = 20
 x2  − 4x + (12/2)^2 + y2 + 12y  + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
 x2  − 4x + (6)^2 + y2 + 12y  + (-2)^2 = 20 + (6)^2 + (-2)^2
 x2  − 4x + 36 + y2 + 12y  + 4 = 20 + 36 + 4
 (x − 2)2 + (y + 6)2 = 60 

 
3x2 + 3y2 + 12x + 18y − 15 = 0 
 
x2 + y2 + 4x + 6y − 5 = 0 
 x2 + y2 + 4x + 6y  = 5 
 x2  + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2 
 x2  + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2 
 x2  + 4x + 4 + y2 + 6y + 9 = 5 + 4 + 9 
 (x + 2)2 + (y + 3)2 = 18 

 2x2 + 2y2 − 24x − 16y − 8 = 0
 x2 + y2 − 12x − 8y − 4 = 0
 x2 + y2 − 12x − 8y = 4 
 x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
 x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
 x2 − 12x + 36 + y2 − 8y + 16 = 4 + 36 + 16
 (x − 6)2 + (y − 4)2 = 56 

 x2 + y2 + 2x − 12y − 9 = 0
 x2 + y2  + 2x - 12y = 9
 x2  + 2x + y2 - 12y = 9
 x2  + 2x + (2/2)^2 + y2 - 12y  + (-12/2)^2 = 9 + (2/2)^2 + (-12/2)^2
 x2  + 2x + (1)^2 + y2 - 12y  + (-6)^2 = 9 + (1)^2 + (-6)^2
 x2  + 2x + 1 + y2 - 12y  + 36 = 9 + 1 + 36
 (x + 1)2 + (y − 6)2 = 46
7 0
3 years ago
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