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2 years ago

A manufacturer of breakfast cereals is considering the following two designs for cereal boxes.

Mathematics

2 answers:

zhannawk [14.2K]2 years ago

5 0

Answer:

Box A

Step-by-step explanation:

6x6x6=216

(72x2)+(18x2)+(36x2)=252

Lyrx [107]2 years ago

4 0

Answer:

He should use box A

Step-by-step explanation:

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Find the volume of each cylinder. Use 3.14 for pi. Round your answer to the nearest tenth

otez555 [7]

Answer:

V ≈471.24 mm^3

Step-by-step explanation:

The formula for cylinder volume is πr^2 x h, so ((π x 25) x h). That's just 25π x 6. That is about 471.238898, which rounded is almost 471.24. Or, in terms of π, you could leave your answer as 150π mm^3

8 0

3 years ago

Help Pls I need the answer to t <img src="https://tex.z-dn.net/?f=0%3D-16t%5E2%2B704t" id="TexFormula1" title="0=-16t^2+7

Xelga [282]

Answer:

t=0 or t=44

Step-by-step explanation:

There are a few methods to do this, the most obvious being the use of the quadratic formula.

However, a quick check with a calculator or even your mind will reveal that 704 is divisible by 16. Thus we can solve this through factoring.

-16t(t-44)=0

Using the zero factor principle:

-16t=0 and so t=0

t-44=0 and so t=44

And thus we get the solution.

7 0

3 years ago

In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control

lianna [129]

Answer:

The sample space for selecting the group to test contains 2,300 elementary events.

Step-by-step explanation:

There are a total of N = 25 aluminum castings.

Of these 25 aluminum castings, n₁ = 4 castings are defective (D) and n₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

Compute the number of samples that are possible as follows:

${25\choose 3}=\frac{25!}{3!\times (25-3)!}$

$=\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300$

The sample space for selecting the group to test contains 2,300 elementary events.

6 0

3 years ago

A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando

Allushta [10]

Answer:

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

Solution:

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

5 0

3 years ago

What is the slope-intercept form of the linear equation 2x–8y=322x–8y=32 ?

gladu [14]

2x - 8y = 32
-8y = -2x + 32
y = (-2/-8)x - 32/8
y = 1/4x - 4 <== slope intercept form

5 0

3 years ago