Question

Question 3 of 10

Answer 1

Answer:

no real solutions

Step-by-step explanation:

the given quadratic equation is 3x²-x+5=0

in the equation:

a=3

b=-1 (in front of the x)

c=5

the quadratic formula is (-b±√(b²-4ac))/2a

substitute the numbers into the formula

(1±√(1-4(3*5))/6

solve the expression under the square root:

√(1-4(3*5))

√(1-4(15))

√(1-60)

√-59

you cannot find the square root of a negative number, so the answer is no real solutions

Hope this helps!