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aniked [119]
2 years ago
12

Here's a problem for the minds-good luck!

Mathematics
1 answer:
Art [367]2 years ago
8 0

Answer:

20%

Step-by-step explanation:

  1. Set up a proportion: \frac{280}{1400} = \frac{x}{100}  
  2. Cross multiply, then divide: 280 × 100 = 28000, 28000 ÷ 1400 = 20
  3. So, 20% were satisfied with their car

I hope this helps!

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Solve for t: t ÷ 5 = 8
DIA [1.3K]

Answer:

Step-by-step explanation:

Equation is t÷5=8

first you multiply 5 on each to cancel it out

t÷5*5=8*5

solve to get

t=40

8 0
3 years ago
For the following system, use the second equation to make a substitution for y in the first equation.
ICE Princess25 [194]

Answer:

It is A

Step-by-step explanation:

2x + y = 5

y + 3 = 2x

From equation 2:

y = 2x - 3

Substituting in the first equation:

2x + 2x - 3 = 5.

5 0
3 years ago
WILL MARK BRAINLIST!!!!!<br><br> 4 |a| +8−a if a=−2
andre [41]

Answer:

18

Step-by-step explanation:

6 0
3 years ago
Given the equation 25x^2y^2-40xy+16=0, find the value of xy.
Volgvan

Answer:

Not rlly sure, might be x=4/5y??? i dont know

4 0
2 years ago
find the gradient of the line joining (3,7) and (6,9). Hence, find the acute angle it makes with the positive x-y axis​
stiv31 [10]

Answer:

33.7 degrees

Step-by-step explanation:

As we go from (3,7) to (6,9), x increases by 3 and y increases by 2.  Thus, the gradient (slope) of the line connecting these two points is

m = rise / run = 2/3.  Using the slope-intercept formula y = mx + b, we obtain

7 = (2/3)(3) + b, or 7 = 2 + b, so we see that b = 5 and y = (2/3)x + 5.  The y-intercept is (0, 5).

Next we find the x-intercept.  We set y = (2/3)x + 5 = to 0 and solve for x:

(2/3)x = -5, or (3/2)(2/3)x = -5(3/2), or x = -15/2, so that the x-intercept is

(-15/2, 0).  This line intersects the x-axis at (-15/2, 0).

Now look at the segment of this line connecting (-15/2, 0) and (0, 5).  Here x increases by 15/2 and y increases by 5, and so the tangent of the acute angle in question is

tan Ф = 5 / (15/2) = 10 / 15 = 2/3.

Using the inverse tangent function, we get Ф = arctan 2/3, or approx.

33.7 degrees.

I believe you meant "the acute angle it makes with the positive x-axis."​

3 0
3 years ago
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