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KIM [24]
3 years ago
7

What are the most common forms of information?

Computers and Technology
1 answer:
scoundrel [369]3 years ago
6 0

Answer: web search

Explanation:

You might be interested in
.Statements using the ___________ class are explicit conversions.
USPshnik [31]

Answer: Explicit

Explanation:

 The statement which used the explicit class are the explicit conversion, as  it is type of the conversion which uses the conversion keyword. These type of the keywords act as a function in the explicit conversion and compiler generating the code in the given inline function.  

Explicit conversion basically require the cast operator in its function when, the information is lost during explicit conversion.

Conversion of base class into the derives class is one of the typical example of the explicit conversion.

3 0
3 years ago
2. You are developing a new application that optimizes the processing of a warehouse’s operations. When the products arrive, the
KonstantinChe [14]

Answer:

Option d) is correct

Explanation:

To optimize the processing of a warehouse’s operations, products are stored on warehouse racks when they arrive. The items that arrive last are the first to go out to minimize the time it takes to retrieve an item. The items that arrive need to be represented and the warehouse should be left in a data structure. The data structure which should you use to represent this situation is a queue.

Option d) is correct

5 0
3 years ago
Sara is writing a program to input her monthly phone bills and output the month name and amount for the month with maximum amoun
guajiro [1.7K]

Answer:

double [] phoneBills = new double[12];

Explanation:

Since the question has requested that an array be difined to hold phone bill for each month. Above declares an array that will hold floating point number (double) and it has been created to hold 12 values representing the months January to December

Values can be added in the array as shown in the program below.

<em>public class PhoneBill {</em>

<em>    public static void main(String[] args) {</em>

<em>    String []  MonthName = {"January", "February", "March", "April", "May", "June", "July", "August",</em>

<em>            "September", "October", "November", "December"};</em>

<em>    double [] phoneBills = new double[12];</em>

<em>        phoneBills[0] = 4.5;</em>

<em>        phoneBills[1] = 4.5;</em>

<em>        phoneBills[2] = 5.5;</em>

<em>        phoneBills[3] = 6.5;</em>

<em>        phoneBills[4] = 3.5;</em>

<em>        phoneBills[5] = 5.5;</em>

<em>        phoneBills[6] = 6.5;</em>

<em>        phoneBills[7] = 7.5;</em>

<em>        phoneBills[8] = 8.5;</em>

<em>        phoneBills[9] = 4.5;</em>

<em>        phoneBills[10] = 3.5;</em>

<em>        phoneBills[11] = 7.5;</em>

<em>        System.out.println("Months and corresponding phone bill");</em>

<em>        System.out.println(Arrays.toString(MonthName));</em>

<em>        System.out.println(Arrays.toString(phoneBills));</em>

<em>    }</em>

<em>}</em>

The output of this program is attached:

3 0
3 years ago
Once a table is inserted into a publication, which two tabs become available?
rusak2 [61]

Answer:

insert i think sry if its wrong :(

Explanation:

7 0
3 years ago
Now suppose there are four links between source and destination (three routers in the path between source and destination). Each
pychu [463]

Answer:

12.1 seconds

Explanation:

Step 1:

Assuming the following data :

N: Size of packet = 30 Mb

T: Transmission rate =  10 Mbps

C: Speed of light in copper = 2 * 10^8 m/s

L: Length of link 5000 km

Step 2:

Calculation of the Transmission delay and the Propagation Delay

Transmission delay = \frac{packet size}{bandwidth} = \frac{30Mb}{10Mbps} = 3s

Propagation delay = \frac{length of link}{speed of light in copper} = \frac{5000*10^3}{2 * 10^8} = 0.025s

Step 3:

Calculation of the end-to -end delay

The end-to-end delay = 4*(Transmission Delay+Propagation Delay) = 4*(3+0.025) = 12.1 seconds

6 0
4 years ago
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