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kotegsom [21]
3 years ago
13

PLEASE HELP WITH THIS I NEED TO PASS

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

x = 0.1875

Step-by-step explanation:

first, you group up all of the same numbers or letters. (2x +2x)

then you solve the problem:

2x ^2 = 2x - 3

4x^2 = -3

16x = 3

16       16

x = 0.1875

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Points S,U, and T are the midpoints of the sides of PQR. Which statements are correct ? 1/2QP=UT 1/2TS=RQ SU=PR SU||RP UT=RP
cricket20 [7]

Answer:

\frac{1}{2} QP = UT

Step-by-step explanation:

GIVEN : In ΔPQR

              S is the mid point of QP

              U is the mid point of PR

              T is the mid point of  QR

Solution :

i) is true i.e \frac{1}{2} QP = UT

Refer the attached file

By mid segment theorem i.e. In a triangle, the line joining the midpoints of any two sides will be parallel to the third side and that same line joining the midpoints is also half of length of third side .

UT is the line joining the two mid points . So, by theorem given above UT is parallel to PQ and  1/2QP=UT.

So, (i) statement is true i.e. \frac{1}{2} QP = UT

6 0
3 years ago
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Murljashka [212]

Answer:

1.5 hours = 1 hour 30 mins

Step-by-step explanation:

3/4 = 0.75

0.75 x 2 = 1.5

5 0
3 years ago
Adding unlike fractions <br><br> 1/2+19/20
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1/2 + 19/20
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An oil tanker breaks apart and starts leaking. As time goes on, the rate at which the oil is leaking out will diminish. Suppose
Alborosie

Answer:

62.77 million gallons

Step-by-step explanation:

Given,

The function that shows rate of leaking oil per minute in after t hours,

R(t) = \frac{0.7}{1+t^2}

∵ 1 hour = 60 minutes ⇒ 3 hours = 180 minutes,

Hence, the quantity of oil leaked out in the first 3 hours,

V(t) = \int_{0}^{180} R(t) dt

=\int_{0}^{180} \frac{0.7}{1+t^2} dt

=0.7 \int_{0}^{180} \frac{dt}{1+t^2}

=0.7[tan^{-1}(t)]_{0}^{180}

=0.7(tan^{-1}(180) - tan^{-1} (0))

=0.7(89.68)

= 62.77 million gallons

5 0
3 years ago
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