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mr Goodwill [35]
3 years ago
12

Solve. y −3 = 1 6 y =

Mathematics
1 answer:
inn [45]3 years ago
6 0

Step-by-step explanation:

y - 3 = 16y original problem

y - 3 - y = 16y - y grouping variables

-3 = 15y Simplification

-3÷15 = 15y÷15 Isolating the variable

-1/5 = y the answer

I hope this helps!!!!!!

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Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.
Levart [38]

Answer:

The standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

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3 years ago
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